please comment for doubts .
A barometer reads a pressure of 135000 Pa. What is the pressure in atm? 1330 atm O 1.33 atm O 135 atm O 1.37 x 101 atm
1 atm = 760 mmHg. If the pressure in a balloon is 2.3 atm, what is the pressure in mm Hg?
A gas occupies 4.23 L at 2.25 atm. What is the volume at 3.46 atm?
U. 2. A barometer measures a pressure of 745 mm Hg. What is this pressure in atm? 0.980 atm d 1.00 x 10 atm а. b. 1.02 atm. е. 0.556 atm 1.03 x 10 atm С. A sample of gas at 4.0 atm and 25.0 mL is heated from 25°C to 40°C. If the pressure remains constant, what 5. is the final volume of the gas? a. 26.2 mL d. 105 mL b. 40.0 mL e. 25.0 mL C. 23.8...
The vapor pressure of Y is 4.590 atm at 330K and 9.180 atm at 380K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). AG330º = kJ/mol AG380º = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values ASO = J/(mol-K) AH = kJ/mol What is the normal boiling point of Y in degrees Celcius? t = Ос What...
The vapor pressure of Y is 2.320 atm at 420K and 5.336 atm at 478K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(u) - Y(9). kJ/mol AG420º = AG478° - kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values 3/(mol-K) AS- AH kJ/mol What is the normal boiling point of Y in degrees Celclus? oc What is the vapor pressure...
The vapor pressure of Y is 4.560 atm at 440K and 13.680 atm at 515K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(l) = Y(g). G440o = -5.55 kJ/mol G515o = -11.20 kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values delta S = J/(mol-K) delta H = kJ/mol What is the normal boiling point of Y in degrees Celcius?...
The vapor pressure of Y is 4.050 atm at 290K and 13.365 atm at 373K. What are the standard free energies of vaporization at the two temperatures? Hint: vaporization reaction is Y(I) = Y(g). «J/mol AG290º = AG373° = kJ/mol Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values J/(mol-K) AS° = AH° = kJ/mol What is the normal boiling point of Y in degrees Celcius? 1 t= t =...
The vapor pressure of Y is 1.620 atm @ 200K and 4.698 atm @ 273K. What are the standard free energies of vaporization temperatures? Hint: vaporization reaction is Y(l) = Y(g) (at 200K) (at 273K) Assume that the standard entropy and enthalpy of vaporization of Y are independent of temperature and determine their values. (Delta S degrees) (Delta H degrees) What is the normal boiling point of Y in degrees Celcius? t= ? degrees Celsius What is the vapor pressure...
20- What is the pressure in atm of a 0.108 mol sample of the gas at a temperature of 20.0°C if its volume is 0.505L? (R=0.0821 L. atm/mol.K) a) 8.14 atm b) 5.14 atm c) 0.20 atm d) 0.35 atm