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please can I have help understanding part C
A block of 20 kg is connected as shown in Figure QA1. Numerical values: k = 600 N/m, c = 40 N.s/m K I Soros (N) Figure QA1. M
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motion is eqh of a mät a cu + 3kn = 0 2oüt 80 i + 1800 n = O ä + uit gon 2 = Go 2) Wn a 9.486 2 rad ve f 2zWnau al 3 0.2108 Ue 2t (c, cos 9. 2736t8 niz + G Sin 9. 2736t) Boundary Cond are; at tao; N 2= 0.olm, V = -0.02 Ję at tio, az 0.01 so, 0.01 J-0.02= -24 + 9. 2736 x G 120 N2 (orol cos 9. 2736+) at ta a 0.25 see 3 u= - 4.1237x10- 4.1237 on m

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