Question

Rf tok Ri 0 +12V 2 Ik ovo 777 3 1-42N Vin 77777

Answer 1

Note: In case of general purpose OPAMP IC 741, pin 2 is the inverting input and pin 3 is non inverting input

Vin is the input applied at non inverting terminal

From virtual ground concept, voltage at the node of inverting input is also Vin

If we apply KCL at this node we get

$\frac{V_{in}}{R_{i}} = \frac{V_{out}-V_{in}}{R_{f}}$

Simplifying, we get

$\frac{V_{out}}{V_{in}} =1+ \frac{R_{f}}{R_{i}}$

As we can see, the given circuits operates as a non inverting amplifier with a gain of $1+ \frac{R_{f}}{R_{i}}$

Here, the as Rf =10k and Ri = 1k, Gain = 11

I have constructed the given circuit on a breadboard in TinkerCAD tool

Both the power supplies used in the circuit are set at 12V, positive terminal of one of the supply goes to the pin 7 of OPAMP IC. Whereas, negative terminal of the other 12V supply goes to the pin 4 of OPAMP. The other two terminals are tied together at ground.

Rest of the components are connected as shown

The input is set at 0.5V/500mV with 10Hz frequency (sine wave)

The output voltage waveform should have the same frequency and a peak to peak amplitude of 0.5*11 = 5.5 V

As can be seen in the simulation, the lower scope shows the input waveform. Y-axis has a span of 1Vp-p.

As input is 500mVp-p, it occupies half the range.

Similarly the y axis span of the scope connected to output is 10Vp-p, so we can see that the output waveform is approximately 5.5Vp-p sine wave in phase with input

Which verifies the calculations above and confirms that the OPAMP is operating as a non inverting amplifier

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