A mass of 0.42 kg is fixed to the end of a 1.53 m long string...
A mass of 0.42 kg is fixed to the end of a 1.53 m long string that is fixed at the other end. Initially at rest, he mass is made to rotate around the fixed end with an angular acceleration of 2.52 rad/s. What centripetal force must act on the mass after 7.91 s so that it continues to move in a circular path?
Homework Answers
A mass of 0.28 kg is fiixed to the end of a 0.93 m long string...
A mass of 0.28 kg is fiixed to the end of a 0.93 m long string that is fixed at the other end. Iniitially at rest, the mass is made to rotate around the fixed end with an angular acceleration of 4.43 rad/s. After how many revolutions is the cetripetal force acting on the mass 502 N ?
2. A rigid sphere with mass 20 Kg and radius 0.6 m is free to rotate...
2. A rigid sphere with mass 20 Kg and radius 0.6 m is free to rotate around a fixed axis passing through its center (I = 2/5 mR2). The sphere is initially at rest. A force of 4 N is applied at the edge (or equator) of the sphere, tangent to the sphere and perpendicular to the sphere radius, generating a constant torque for 3 s. (i) Calculate the magnitude of the angular acceleration of the sphere. (ii) Calculate the...
1. M, a solid cylinder (M=2.03kg, R=0.137m) pivots on a thin, fixed, frictionless bearing. A string...
1. M, a solid cylinder (M=2.03kg, R=0.137m) pivots on a thin,
fixed, frictionless bearing. A string wrapped around the cylinder
pulls downward with a force F which equals the weight of a 0.670kg
mass, i.e., F = 6.573N. Calculate the angular acceleration of the
cylinder. (Answer in rad/s2.)
2. If instead of the force F an actual mass m = 0.670kg is hung
from the string, find the angular acceleration of the cylinder. Use
units of "rad/(s*s)
1. M, a...
M, a solid cylinder (M=2.23 kg, R=0.131 m) pivots on a thin, fixed, frictionless bearing. A...
M, a solid cylinder (M=2.23 kg, R=0.131 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.870 kg mass, i.e., F = 8.535 N. Calculate the angular acceleration of the cylinder. 5.84×101 rad/s^2 If instead of the force F an actual mass m = 0.870 kg is hung from the string, find the angular acceleration of the cylinder. How far does m travel...
A block of mass m = 1.7 kg is attached to a string that is wrapped...
A block of mass m = 1.7 kg is attached to a string that is wrapped around the circumference of a wheel of radius R = 7.5 cm . The wheel rotates freely about its axis and the string wraps around its circumference without slipping. Initially the wheel rotates with an angular speed ω, causing the block to rise with a linear speed v = 0.42 m/s .(Figure 1) Find the moment of inertia of the wheel if the block...
M, a solid cylinder (M=1.39 kg, R=0.111 m) pivots on a thin, fixed, frictionless bearing. A...
M, a solid cylinder (M=1.39 kg, R=0.111 m)
pivots on a thin, fixed, frictionless bearing. A string wrapped
around the cylinder pulls downward with a force F which equals the
weight of a 0.570 kg mass, i.e., F = 5.592 N. Calculate the angular
acceleration of the cylinder. (the answer to this is 39.8 rad/s^2)
The cylinder is changed to one with the same mass and radius, but a
different moment of inertia. Starting from rest, the mass now moves...
If a particle of mass m = 0.2 kg is performing a circular motion with angular...
If a particle of mass m = 0.2 kg is performing a circular motion with angular velocity ω = 4.0 rad/s and a radius of r = 1.2 m, find: (a) the moment of inertia of the particle, (b) its linear velocity around the circle, (c) its centripetal (radial) acceleration, and (d) its angular momentum
A 2.7-kg 12-cm-radius cylinder, initially at rest, is free to rotate about the axis of the...
A 2.7-kg 12-cm-radius cylinder, initially at rest, is free to rotate about the axis of the cylinder. A rope of negligible mass is wrapped around it and pulled with a force of 18 N. (a) Find the magnitude of the torque exerted by the rope. N · m (b) Find the angular acceleration of the cylinder. rad/s2 (c) Find the angular velocity of the cylinder at t = 0.70 s. rad/s
A diving board has length of 1.8 m and a total mass of 50 kg. However,...
A diving board has length of 1.8 m and a total mass of 50 kg. However, the mass is not uniformly distributed, so its center of mass is off center as shown in the diagram below. However, we know that the moment of inertia around the center of mass is 15 kg m². The board is fixed to rotate around its far left end. A support pushes up with a force of 750 N at the midpoint of the board...
A diving board has length of 1.8 m and a total mass of 65 kg. However,...
A diving board has length of 1.8 m and a total mass of 65 kg. However, the mass is not uniformly distributed, so its center of mass is off center as shown in the diagram below. However, we know that the moment of inertia around the center of mass is 20 kg m². The board is fixed to rotate around its far left end. A support pushes up with a force of 750 N at the midpoint of the board...
1. M, a solid cylinder (M=2.03kg, R=0.137m) pivots on a thin,
fixed, frictionless bearing. A string wrapped around the cylinder
pulls downward with a force F which equals the weight of a 0.670kg
mass, i.e., F = 6.573N. Calculate the angular acceleration of the
cylinder. (Answer in rad/s2.)
2. If instead of the force F an actual mass m = 0.670kg is hung
from the string, find the angular acceleration of the cylinder. Use
units of "rad/(s*s)
1. M, a...
M, a solid cylinder (M=1.39 kg, R=0.111 m)
pivots on a thin, fixed, frictionless bearing. A string wrapped
around the cylinder pulls downward with a force F which equals the
weight of a 0.570 kg mass, i.e., F = 5.592 N. Calculate the angular
acceleration of the cylinder. (the answer to this is 39.8 rad/s^2)
The cylinder is changed to one with the same mass and radius, but a
different moment of inertia. Starting from rest, the mass now moves...
A diving board has length of 1.8 m and a total mass of 50 kg. However, the mass is not uniformly distributed, so its center of mass is off center as shown in the diagram below. However, we know that the moment of inertia around the center of mass is 15 kg m². The board is fixed to rotate around its far left end. A support pushes up with a force of 750 N at the midpoint of the board...
A diving board has length of 1.8 m and a total mass of 65 kg. However, the mass is not uniformly distributed, so its center of mass is off center as shown in the diagram below. However, we know that the moment of inertia around the center of mass is 20 kg m². The board is fixed to rotate around its far left end. A support pushes up with a force of 750 N at the midpoint of the board...
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