Question

write in C language

Decoration Lights Jojo is currently working in an office as a security. Every night, after everyone returned home, he needs to make sure all decoration lights in the office is turned off. The decoration lights are unique: each of them has a timer that will switch the light on or off every two seconds. The lights are also arranged so well that each two neighboring lights will have different state (on/off). As long as the timer is on, the lamp will continue to be switched on/off. Jojo can shut down a timer in one second. However, if the light is currently switched on, he will need another second to switch it off before he can shut its timer down. Assuming he can only work on a lamp before moving to the next lamp, help Jojo's wife to determine how many seconds Jojo need to do his work before he can return home. Format Input The first line in the input is an integer T, the number test case. Each test case consists of two lines. The first line consists of integer N, denoting the number of decoration light in the office. The next line consists of N integers denoting the state of the lamps when Jojo is trying to turn them off. The lamp state is guaranteed to be between "0" or "1", representing whether the light is off or on respectively. Format Output For each test case, output "Case X: " followed by how many seconds Jojo need to turn off all the decoration lights. Constraints 1ST < 30 1SN S 50000 Page 1 of 2 Sample Output Case 1: 6s Case 2: 6s Sample Input 2 3 1 0 1 6 010101 Explanation On the first case, Jojo need two seconds to turn off both light and timer for the first lamp. By the time he finished it, the second lamp already switched on by its timer. Jojo spend another two seconds on the second lamp, and four seconds passed before he can lay hand on the third lamp, which should be switched on by that time. Jojo spend two final seconds and by the time all lamps turned off, he has already spent 6 seconds Note: Don't forget to add the newline character after printing the output.

Answer 1

Hello dear...

Here is the C program for the given problem statement. The logic is too simple. It was given that, each two neighbouring lights will have different state(on/off).

So, if the first light state is off(0) then he can switch off all N lights in N seconds.

Else if the first light is on(1) then he have to waste 1 extra second to turn off both light and timer for all N lights. So total time will be 2*N seconds.

Thats it. Here is the C program. I have also written comments for better understanding. Also attached images of output and code for your comfort.

main.c

#include <stdio.h>

//main method
int main() {
    //declare required variables
    int T,N,i,j;
    //take input for no. of test cases
    scanf("%d", &T);
    //run loop for T times
    for(i=0; i<T; i++){
        //take input for number of lights
        scanf("%d", &N);
        //create array to store states of N lights
        int states[N];
        //take states of all N lights as input 
        for(j=0; j<N; j++){
            scanf("%d", &states[j]);
        }
        //if first lamp is on
        if(states[0]==0)
            //print N seconds for given test case 
            printf("Case %d: %ds\n", i+1, N);
        else
            //print N*2 seconds for given test case
            printf("Case %d: %ds\n", i+1, N*2);
    }
    //end
    return 0;
}

input:

2 3 101 6 01010

Output:

OUTPUT Case 1: 6s Case 2: 6s

image of code:

8 9 14 1 #include <stdio.h> 2 3 //main method 4 int main() { 5 //declare required variables 6 int T,N,i,j; 7 //take input for no. of test cases scanf("%d", &T); //run loop for T times 10 for(i=0; i<T; i++){ 11 //take input for number of lights 12 scanf("%d", &N); 13 //create array to store states of N lights int states [N]; 15 //take states of all N lights as input 16 for(j=0; j<N; j++){ 17 scanf("%d", &states[j]); 18 19 //if first lamp is on 20 if(states [O]==0) 21 //print N seconds for given test case 22 printf("Case %d: %ds\n", i+1, N); 23 else 24 //print N*2 seconds for given test case 25 printf("Case %d: %ds\n", i+1, N*2); 26 } 27 T/end 28 return 0; 29 } }

Hope you like it.

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​​​​​​All the best.