A simple circuit is constructed by connecting one voltage source E Volt with one resistor resistor...
A simple circuit is constructed by connecting one voltage source E Volt with one resistor resistor R Ohm and current is measured 1.48 Amps. If the voltage of the source is TWICE and resitor is ONE-THIRD of their previous values, what is the new current?
Homework Answers
current i= 1.48 A
using ohms law
E = i R
i= E/R
so 1.48= E/R -------------------------(1)
new voltage = 2 E and new resistance = R / 3
new current = (2 E)/ (R / 3)
new current = 6 (E / R)
we plugin the value of E/R = 1.48 from equation 1
new current= 6 * I = 6 * 1.48
new currenr= 8.88A
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