5. In biological systems, production rate of glucose is 0.6 μ g mol/(mL)(min). Determine the production...

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5. In biological systems, production rate of glucose is 0.6 μ g mol/(mL)(min). Determine the production rate of glucose for this system in the units of lb mol/(f3)(day).

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Answer 1

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Production rate of glucose = 0.6 $\mu$ gmol/(mL-min)

Change it into required units

1 lbmol = 453.592*10^6 $\mu$ gmol

1 ft3 = 28316.8 mL

1 day = 1440 min

Production rate of glucose

= [ 0.6 $\mu$ gmol/(mL-min)] x [1lbmol/453.592*10^6 $\mu$ gmol] x [28316.8 mL/ft3] x [1440 min/day]

= 0.0539 lbmol/(ft3-day)

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Answer 2

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5. In biological systems, production rate of glucose is 0.6 μ g mol/(mL)(min). Determine the production...

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