Question

Exercise 2-b: Try to complete the following table based on the required specification: Number of usable hosts per subnet in need: 8000 Network address: 135.70.0.0 You need to show how you worked out the solution Address Class class B Default subnet mask 255.255.0.0 Custom subnet mask 19 255.255.224.0 Total number of subnets 123 - 2 Creserved) = 8192 -2 = 8190 Total number of host addresses per subnet Number of usable addresses per subnet Number of bits borrowed What is the 3rd subnet range? What is the subnet number for the 2nd subnet? What is the subnet broadcast address for the 1st subnet? What is the first assignable addresses for the 1st subnet? nats

Can I have the rest answers step by step please.

Answer 1

Solution for the problem is provided below, please comment if any doubts:

Your total number of subnets answer is wrong, so I start from that portion, the explanation/computation is added for each part. Please comment if any doubts:

Total number of Subnets	Number of address possible using bits allotted for sub net. 3 bits are allotted for subnets Thus Total number of sub nets = 23 = 8
Total number of host address per subnet	Total number of host address possible using 13 bits allotted for host allocation in the scenario Total number of host address per subnet = 2^13= 8192
Number of usable address per subnet	Total number of host address minus 2 reserved address Number of usable address per subnet = 8192-2 = 8190
Number of bits borrowed	It is the number of bits taken from host bits to allocate the host address, here 3 bits are taken from total 16 bits allocated for host address t Thus number of bits borrowed = 3
What is the third subnet range	For the third subnet, the first 16 bits are same as that of the network address, that is 135.70. Next three bits will be 010 for the third subnet Rest 13 bits will be allocated for the hosts. Thus the 3rd subnet range = 135.70.64.0 - 135.70.95.255
What is the subnet number for the 2nd subnet?	The second subnet bits for the second octant first three bits are = 001 Thus subnet number of 2nd subnet= 135.70. 32
What is the subnet broadcast address for the 1st subnet?	The first subnet will have first three bits are = 000 The broadcast address will have all 1’s for the host part. Thus the subnet broadcast address for the 1st subnet = 135.70.00011111.11111111, in decimal Thus the subnet broadcast address for the 1st subnet = 135.70.31.255
What is the first assignable address for the 1st subnet?	The first assignable address for the 1st subnet = the host part address with all zeros except last bit. Thus the first assignable address for the 1st subnet = 135.70.0.1