Question

Problem 2: In a given lab session a group of students performed a sequence of thermodynamic processes to a given gas. Before performing the process the studenta recorded the initial pressure of the gas as being 101.5 kPa and its temperature equal to 2000 The sequence can be described as firstly isochoric heating in which the gas temperature is increased by 25% of its initial temperature, followed by an isothermal compression in which the volume of the gas is reduced in 50% and finished with an isobaric colling where the gas temperature is decreased in 75%. Based on the above description determine the gas pressure, temperature and specific volume (m3/mol) after each process. Hint: Your final answer must contain 4 distinct values of pressure, temperature and specific volume.

Answer 1

② Pi= 101.5 kPa Ti = 350 = 308k T2 = 1.25 T = 1.25 x 308 = 385k V = 1₂ ₂=0.5 V2 = 0.5V T3 = 0.75 T = 0.75 +385= 288.75k Isochoric Process 1-2 P2 = 101.5x1.25 P₂ = 126.875 kPa = P3 By Ideal gas equation PV = nRT P. V=RIT, where, R= 8.314 J/molk

101.5x103* v, - 8.314 x 308 y = 0.0252 m/mol = 2 z = 0.5 vi - 0.5 x 0.0252 z = 0.012614 mi/mol State I TLK) 308 P(kPa) 101.5 V(m/mol) 0.0252 State 2 385 126 875 0.0252 State 3 288.75 126875 0.012614

3.

(-) sign indicates that work is done by the process, as total work is also (-) so it is done by the cycle.

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