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Gears, Splines, and Cams 410 25 H7 m 8J9 + A AM 20*0,2 20 NUMBER OF TEETH 18 IMODULE 6 PRESSURE ANGLE 20° PITCH DIAMETER 108 TOOTH FORM STD INVOLUTE MAX.CALC. CIRCULAR THICKNESS ON STD. 9.425 PITCH DIAMETER AGMA QUALITY CLASS 5 25 H7 +21 0 8J9 +18 -18 Worksheet guide for questions 6-11. Round off answers to three decimal places. Worksheet 13-1

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Answer 1

Work sheet 13-1

1. Type of gear = Spur gear

2. Module, M = 6mm

3. Number of teeth, N = 18

4. Pressure Angle = 20$\degree$

5. Number of keyways = 1

6. Pitch diameter, PD = N x M = 18 x 6 = 108 mm

7. Addendum, Ad = 1 x M = 1 x 6 = 6 mm

8. Dedendum, Dd = 1.5 x M = 7.5 mm

9. Root diameter, RD = PD - 2(Dd) = 108 - (2 x 7.5) = 93 mm

10. Outside diameter, OD = PD + 2(Ad) = 120 mm

11. Circular Pitch, CP = 3.146 x M = 3.146 x 6 = 18.876 mm

12. Maximum dimension = 8mm + 18 micron = 8.018 mm

13. Minimum dimension = 8mm - 18 micron = 7.982 mm

14. Maximum roughness height in micrometers = 0.8 microns

15. Maximum dimension = 25mm + 21 microns = 25.021 mm

16. Minimum dimension = 25mm + 0 microns = 25 mm

Work sheet 13-3

1. Type of gear = Spur gear

2.Diametrical pitch, DP = 8 in-1

3. Number of teeth, N = 28

4. Material = 4140 STEEL

5. Number of keyways = 1

6. Pressure angle = 20$\degree$

7. Pitch diameter, PD = N / DP = 28 / 8 = 3.5 in

8. Addendum, Ad = 1 / DP = 1 / 8 = 0.125 in

9. Dimension = 1.114 - 0.5 = 0.614 in

10. Dimension = 0.156 in

11. Dimension = 2 in

12. Dimension = 1 - 0.438 - 0.218 = 0.344 in

13. Dimension = (2 - 1) /2 = 0.5 in

14. Dimension = 0.5 - 0.156 =

15. Dimension = 0.344 in

16. Dimension = 1.114 + 0.5 + 1.614 mm

Work sheet 13-7

1. Type of gear = Spur gear

2. Diametrical Pitch, Dp = 8 in-1

3. Number of teeth, N = 32

4. Material = CAST IRON

5. Pitch diameter, PD = N / DP = 32 / 8 = 4 in

6. Addendum, Ad = 1 / Dp = 1 / 8 = 0.125 in

7. Outside diameter, OD = PD + 2(Ad) = 4 + 2(0.125) = 4.25 in

8. Dimension = 1.114 + ((1.175 - 1) / 2) = 1.489 in

9. Dimension = 1.114 - 0.5 = 0.614 in

10. Dimension = (3.25 - 1.75) / 2 = 0.75 in

11. Maximum dimension = 1.114 in

12. Dimension = ((3.25 - 1) / 2) + 1 = 2.125 in

13. Dimension = 1 - (0.5/2) = 0.75 in

14. Dimension = (1 - 0.25) / 2 = 0.375 in

15. Dimension = (1 - 0.75) / 2) + 1 = 1.125 in

16. Dimension = (1 - 0.75) / 2) = 0.125 in

I have tried answering as many as i can in the given time. Sorry because i have not answered full

i will answer the rest if i get another chance.

Thank you.

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