Question

A 208-V three-phase motor runs 1,770 rpm at a load requiring 5 N-m torque. The motor draws 6.5 A of current and the power fac
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Answer #1

Power output =Torque *angular speed

Angular speed should be in rad/sec

Therefore above question power output=5*2*pi*ns

Pi=3.14

ns is the rotation per sec=rotation per minute/60

Which gives output power=926.769W

Input power =(3)^.5 *(supply voltage)*(supply current) * power factor......( As this is three phase supply)

Supply voltage=208V

Supply current=6.5A

Power factor=.88

Which gives us input power =2060.72W

Therefore losses in machine=input power - output power

Which gives losses=1133.95W

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