Question

Solve multiple choice pleassee???

02: Choose the correct answer for the above amplifier pointleach) 1. The amplifier in figure (1) is operating in: i) Saturation mode ii) Triode mode iii) Cutoff mode 2. The configuration of the above amplifier is: i)Common Drain ii) Common Source with R, i) Common Gate 3. To measure Rin Experimentally, the added resistor (RD) should be connected to the circuit: i) in parallel with input ii)in parallel with output ii) in series with input 4. The given curve represents the relation between (mA) versus Vos for a MOSF transistor: VID(MA) vs. Vas VIDMA) ONES vos A) K (mA/V") for Mi transistor equals to: iv) i) 15 ii)2 B) V. (V) equals to: 1) 2 (i) 1) iii) 3 C) The relation between Ip versus Vos fort Mosfet is: i) Exponential ii) Linear iii) Parabolic iv) cubic

with fig1

Answer 1

Given problem has been solved with proper explanation and explanation. To understand this problem a basic knowledge of MOSFET and it's characteristics are required. If you have any doubt, please comment.

BD TOV Mi I fim fs figure a Q2 1. The amplifier im Figure 1 is operating in - Saturation mode, because the amplifier circuit must be operated in saturation region to maintain full swing of import signal (AC) to output signal. . In cut off and triode region, full swing of input signal can not be possible. In this case, distorted output signal will be formed. Proper amplification is not possible in cutoff and triode region. In . Saturation of Saturation region In: VDO R: to Ros K outpnt amplified Signal Tride Tride region 15. K Nos - cutoff region Input signal

2. The configuration of the above amplifies és Common source with Res because for drain and gate the common terminal is source connected with Rs. 3. To measure Rim experementally, the added resistor (RD) should be connected to the circuit in parallel withoutput because to Rim experimentally all the present sources must be a rounded, then Rp will be parallel with output. 4. The given curve represents the relation between JID(ma) versus vas for a MOSFET transistor. VID (MA) supe: 2 = 2 (mA) ----

A « (mA/2) For Ms trammistos equal to : e: (slope) = (2)= a man B) V+ (w) equals to : ID = k cvas - vt) — 0 Let us take a point from the JJp vs vas plot. (170, vas) - (2-2) .Io = (2)9= 4 ma Vas = 20 • axios 4x108 (2-vt) [fum equatim ©] * 12-Vt Vt=2-1 = 1 :: Vt (v) equals to 1 c) The relation between Is versus Vas. For t MOSFET is - Parabolêe Ip = k (Vas - vy) this equation is similar to the equation of parabola y=x?