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A CT of ratio of 200:5 is used in a relaying application where the burden impedance is 0.5 ohms. If the pick-up current valueA CT of ratio of 200:5 is used in a relaying application where the burden impedance is 0.5 ohms. If the pick-up current value is 5 A, what is the line current required to trip the relay? Also what is the CT error? Hint: Calculate the total secondary current using the graph (I_s=I_e+I_pc) then find the line current using the CT ratio.

POWER SYSTEMS PROTECTION



Excitation curves for CTS Secondary exciting volts-E 600:5 ++++ 500:5 -450:51 HAN 400:57 LING CTSecondary ratio resistance 12
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Answer Given. CT ratio = 20005 Burden Impedance = 0.52 pick up current = SA from the CT graph (For 20085) Z, = 0.125 SecondarTo get rated secundary current , we go to knee point At knee point - E= 40V, Is = 1A = 1pc In = 40 i Secondary current 0.5 +0

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