What is the phenotypic ratio expected after a dihybrid self cross displaying dominant suppression? How do...
What is the phenotypic ratio expected after a dihybrid self cross displaying dominant suppression?
How do you work this out? I know its 13:3 but how do they get this?
Homework Answers
In dominant suppression epistasis the dominant form of a gene inhibits the expression of another gene. A dihybrid cross between two heterozygous parents will produce an F2 ratio of 13:3.
Dominant suppression of a dominant allele:
Here Phenotypic ratio is 13:3
Example:For a hypothetical gene B
where B- = mutant and bb = wt, consider a dominant suppressor where A- = suppression of B- and
aa = no suppression
Then, Selfing heterozygotes (AaBb) -------- -,we get:
9/16 A-B- wt (due to suppression)
3/16 A-bb wt
3/16 aaB- mutant
1/16 aabb wt
Thus the total phenotypic ratio is: 13/16 wt and 3/16 mutant.
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