Homework Answers
Convert the instruction in binary and decode to instruction based on bit position.
20090014 => ADDI $t1 $zero 0x0014 Binary: 00100000000010010000000000010100
00005024 => AND $t2 $zero $zero Binary: 00000000000000000101000000100100
01495020 => ADD $t2 $t2 $t1 Binary: 00000001010010010101000000100000
00094840 => SLL $t1 $t1 0x0undefined Binary: 00000000000010010100100001000000
1520fffd => BNE $t1 $zero 0xFFFD Binary: 00010101001000001111111111111101
3c081001 => LUI $t0 0x1001 Binary: 00111100000010000001000000000001
ad090000 => SW $t1 0x0000 $t0 Binary: 10101101000010010000000000000000
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2. The following is part of a MIPS program in machine code. Decode this code and...
Question 3 (10 points) Convert the following MIPS assembly code into machine language. Write the instruction...
Question 3 (10 points) Convert the following MIPS assembly code into machine language. Write the instruction in hexadecimal. The opcode for sw 43 (101011). sw St1, -4(St3) Question 4 (10 points) Consider the following MIPS assembly code: addi $s3, $0, 5 addi $s1, S0, 3 addi Ss1, $s1, 2 beq Ss3, Ssl, target addi Ss1, Ss1, 1 target: add Ss3, Ss1, Ssl a. After running the code, what is the value of Ss3? b. If the memory address of the...
its brr[8] (40%) Convert the following C-pseudo code into MIPS assembly code as a standalone program...
its
brr[8]
(40%) Convert the following C-pseudo code into MIPS assembly code as a standalone program (including main and all the required directives). You can use any register. You must comply, however, with the convention of register usage. Before writing your code perform an explicit register allocation phase. Note that the C snippet is int arr[8]; int brr[4]-{1, 2, 3, 4, 5, 6, 7, 8) int i-8; while (i>-0) arrli]-brr[i-); (40%) Convert the following C-pseudo code into MIPS assembly code...
CDA-3101 – MIPS Assembly Programming 1. Write the following code segment in MIPS assembly language code:...
CDA-3101 – MIPS Assembly Programming 1. Write the following code segment in MIPS assembly language code: 3. Write a MIPS program to find the sum of squares from 1 to n. Where n=10. For example, the sum of squares for 10 is as follows: 12+22+32+……+n2=385
Compiling C Programs into MIPS Assembly and Machine Code sll $t1, $a1, 2 add $t1, $a0....
Compiling C Programs into MIPS Assembly and Machine Code sll $t1, $a1, 2 add $t1, $a0. $t1 lw $t0, 0($t1) lw $t2, 4($t1) sw $t2, 0($t1) sw $t0, 4($t1) 1. From the assembly code, what machine code might a MIPS assembler produce? 2. What does this program do? Write the C code for this assembly program.
IN MIPS MACHINE LANGUAGE FOR MARS SIMULATOR Write your own short program that presents a RAW...
IN MIPS MACHINE LANGUAGE FOR MARS SIMULATOR Write your own short program that presents a RAW data dependence condition (2-5 instructions in MIPS that exhibits a data hazard). Document the hazard condition in your code comments.
B2. Translate the following MIPS assembly instruction into machine language: lw $t8, 100($s0) B3 ...
B2. Translate the following MIPS assembly instruction into machine language: lw $t8, 100($s0) B3 Write MIPS assembly code segment for the following C code snippet: for (i - O i < 10i i++) i array[i+l] - array [i8; Register assignment: i-> Şa0 Base of array -> $s0
B2. Translate the following MIPS assembly instruction into machine language: lw $t8, 100($s0) B3 Write MIPS assembly code segment for the following C code snippet: for (i - O i Şa0 Base of...
Convert the following instructions from MIPS assembly language to machine language add $50, $t0, $s3 (op...
Convert the following instructions from MIPS assembly language to
machine language
add $50, $t0, $s3 (op code: 0, function code: 32) sub $t9, $50, $zero (op code: 0, function code: 34) addi $s2, $t0, 16 (op code: 8, function code: Does not exist for I-type instructions)
Name B. (7 pts) MIPS short answer 1. (3pt) For the following MIPS assembly language program:...
Name B. (7 pts) MIPS short answer 1. (3pt) For the following MIPS assembly language program: loop: addi Sto, $to,-1 bne $to, $zero, loop Translate the second instruction into MIPS machine language and write it in hex. 2. (2 pt) Which best describes the reason that we maintain the stack pointer in a register? (circle one) i. The hardware forces use of a stack pointer. ii. We need a local pointer because we are often limited to relative addressing. ili....
For exercises 3 through 5: .Convert the given high level language pseudocode into MIPS assembly *...
For exercises 3 through 5: .Convert the given high level language pseudocode into MIPS assembly * Use proper indentation for code blocks within conditional statements and loops Comment each assembly instruction to indicate the high-level language operation it is performing: .Use MARS to verify correct operation of your program
For project six, you will be given a list of MIPS machine language code instructions in...
For project six, you will be given a list of MIPS machine language code instructions in memory. Your task is to Disassemble the contents and show the MIPS instructions. Make sure to calculate the correct branch target address for each branch instruction. If the resulting BTA happens to be outside the given code, this is OK, just make sure you calculate the BTA correctl Contents Address 0x00400024 Ox3c111001 0x00400028 Ox3410000a 0x0040002c Ox2a01000a 0x00400030 0x14200006 0x00400034 Ox8e280000 0x00400038 Ox01094820 0x0040003c Ox22100001...
Question 3 (10 points) Convert the following MIPS assembly code into machine language. Write the instruction in hexadecimal. The opcode for sw 43 (101011). sw St1, -4(St3) Question 4 (10 points) Consider the following MIPS assembly code: addi $s3, $0, 5 addi $s1, S0, 3 addi Ss1, $s1, 2 beq Ss3, Ssl, target addi Ss1, Ss1, 1 target: add Ss3, Ss1, Ssl a. After running the code, what is the value of Ss3? b. If the memory address of the...
its
brr[8]
(40%) Convert the following C-pseudo code into MIPS assembly code as a standalone program (including main and all the required directives). You can use any register. You must comply, however, with the convention of register usage. Before writing your code perform an explicit register allocation phase. Note that the C snippet is int arr[8]; int brr[4]-{1, 2, 3, 4, 5, 6, 7, 8) int i-8; while (i>-0) arrli]-brr[i-); (40%) Convert the following C-pseudo code into MIPS assembly code...
B2. Translate the following MIPS assembly instruction into machine language: lw $t8, 100($s0) B3 Write MIPS assembly code segment for the following C code snippet: for (i - O i < 10i i++) i array[i+l] - array [i8; Register assignment: i-> Şa0 Base of array -> $s0
B2. Translate the following MIPS assembly instruction into machine language: lw $t8, 100($s0) B3 Write MIPS assembly code segment for the following C code snippet: for (i - O i Şa0 Base of...
Convert the following instructions from MIPS assembly language to
machine language
add $50, $t0, $s3 (op code: 0, function code: 32) sub $t9, $50, $zero (op code: 0, function code: 34) addi $s2, $t0, 16 (op code: 8, function code: Does not exist for I-type instructions)
Name B. (7 pts) MIPS short answer 1. (3pt) For the following MIPS assembly language program: loop: addi Sto, $to,-1 bne $to, $zero, loop Translate the second instruction into MIPS machine language and write it in hex. 2. (2 pt) Which best describes the reason that we maintain the stack pointer in a register? (circle one) i. The hardware forces use of a stack pointer. ii. We need a local pointer because we are often limited to relative addressing. ili....
For exercises 3 through 5: .Convert the given high level language pseudocode into MIPS assembly * Use proper indentation for code blocks within conditional statements and loops Comment each assembly instruction to indicate the high-level language operation it is performing: .Use MARS to verify correct operation of your program
For project six, you will be given a list of MIPS machine language code instructions in memory. Your task is to Disassemble the contents and show the MIPS instructions. Make sure to calculate the correct branch target address for each branch instruction. If the resulting BTA happens to be outside the given code, this is OK, just make sure you calculate the BTA correctl Contents Address 0x00400024 Ox3c111001 0x00400028 Ox3410000a 0x0040002c Ox2a01000a 0x00400030 0x14200006 0x00400034 Ox8e280000 0x00400038 Ox01094820 0x0040003c Ox22100001...
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