How many electrons leave the battery per minute?
V=9 V
Resistance R= 2.7 ohm.
Curve (i)=V/R=9/2.7A .............(1)
Current is charge leaving the battery per sec.
i=Q/t
Q=it ............(2)
Magnitude of char on electron =e=1.6x10-19 c.
Let number of electrons leaving the battery is n.
Charge on n electrons:-
Q=ne=it ( from equation 2 )
t=one minute =60 sec
n=it/e =(9/2.7)x60/(1.6x10-19 ) =200/(1.6x10-19)
n=1.25x1021 electrons Ans.
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