Question

Check My Work (11 13. O Video eBook Consider the following hypothesis test: H: =18 H:+18 A sample of 48 provided a sample mean I - 17 and a sample standard deviation 4.5. If requires, round your answers to two decimal places. Enter negative values as negative numbers. a. Compute the value of the test statistic. -1.54 b. Use the t distribution table (Table 2 in Appendix B) to compute a range for the p-value. p-value is between 0.05 and 0.20 c. At a = 0.05, what is your conclusion? p-value is greater than 0.05, do not rejecte VOH d. What is the rejection rule using the critical value? Reject Hift is not equal to -2.012 7 or tis equal to 2.012 What is your conclusion? t=2.012 , do not reject H Hide Feedback Partially Correct Check My Work (1 ren - Icon Key Exercise 09.24 (Self-Test) Question 1: Submit Assignment for Save

Answer 1

null hypothesis: HO: Alternate Hypothesis: Ha: 0.05 level with two tail test and n-1= 47 df, critical t= 2.012 Decision rule reject Ho if absolute value of test statistict|>2.012 18 population mean = sample mean 'x= sample size n= sample std deviation sa std error 'sx=s/Vn- 17.000 48.00 4.500 0.6495 test statt ='X-)vn/sx= p value = -1.540 0.1304

a)

test statistic = -1.54

b)p value is between 0.10 and 0.20

d(

if t is less than or equal to -2.012 or t is greater than or equal to 2.012

t =-1.540