for the reaction abc + d <---> ab + cd, the change in Hrxn= -75 kj/mol, and Ea(fwd) is 235 kj/mol. assuming one step reaction, caluclate Ea(rev)
Ea for reverse reaction = 235 + 75 = 310 KJ / mol
abc + d <---> ab + cd Hrxn= -75 kj/mol
by given data forward reaction is exothermic. so reverse reaction should be endothermic. so forward activation energy + released energy = activation energy for backward reaction
for the reaction abc + d <---> ab + cd, the change in Hrxn= -75 kj/mol,...
Enter your answer in the provided box. For the reaction ABC+D=AB + CD AH' =-65 kJ/mol and Ea(fwd) = 305 kJ/mol. rxn Assuming a one-step reaction, calculate Ea(rev)- kJ/mol
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in the vessel? 16.56 For the reaction A(g)+ B(g) AB(g), how collisions between A and B are possible if 1.01 mol of A(g) and 2.12 mol of B(g) are present in the vessel? many unique 16.57 At 25°C, what is the fraction of collisions with energy equal to or greater than an activation energy of 100. kJ/mol? 16.58 If the temperature in Problem 16.57 is increased to 50.°C by what factor does the fraction of collisions with energy equal to...
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