Question

To determine the angle of twist on a composite rod given the geometry and externally applied torques, to properly apply a sign convention to determine the angle of twist, to use a torque diagram to aid in determining the angle of twist, and to determine the maximum applicable torque given a maximum allowable angle of twist. The rod shown below is made of two different materials. Segment AB is made of aluminum (G=3.9 x 106 psi). Segment BC is bonded to segment AB and is made of brass (G=5.6 x 106 psi). Segment BC is hollow and has an inner diameter of di = 0.9 in. External torques are applied to the rod at point B and point C. Let L A = 59.0 in LB = 48.0 in, da = B dB LA TB Тc LB

Answer 1

'B # Alu HI the D - OBA BA TB It is given by A) Angle of twist at point B., OG torsion Beation that from TGALBA GBAXTA At any cross section b/w Asia &T=0 T IS 19 Kiplin =) TBA = 19 kipin TA-T T=0 & J = Polar moment of inert, a TA = 6 + 13 kip.in TA=19 kipin I (3:2) in given, dAB=2A = 3.2 in LBA=LA-59 in hc. C 4 J = I dag 32 32

6 7) OBA x 59 19x103 3.98006 * (3-2) GBA = 3.9810 86/in? OBA S 08-04 (CASOS fixed) = 0.027922 yad OBA BA = 0.027922 rad =) O3 = 1.5998 B ) 1 Yad = 180 TT o at cir It is given by = TAR LAB МАР ТАВ » Өe LBC 18 x Тос GBCJBC At any cls between BEC, the torque is, Toc To = 13 kipin LBC LB = 48 in. Тge ko
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