If you were to build the cache memory from problem 1 (provided below), what is the...
If you were to build the cache memory from problem 1 (provided below), what is the total size (in bytes) required for this cache memory? The total size includes data, tag, and valid bit chips. Hint: your solution might not be a power of 2.
Total cache memory is 128k bytes
Cache block size is 4 words (1 word = 4 bytes)
CPU address window = 32 bits
Cache memory chip size = 4k x 8-bits
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If you were to build the cache memory from problem 1 (provided
below), what is the...
Cache question computer architecture A cache holds 128 words where each word is 4 bytes. Assuming...
Cache question computer architecture A cache holds 128 words where each word is 4 bytes. Assuming a 32-bit address, for each of the following organizations, complete the table. a.A direct-mapped cache with block size = 16words b.2-way set-associative cache with block size = 8words c.4-way set-associative cache with block size = 4words d.A fully associative cache with block size = 2words. Cache a Cache b Cache c Cache d total # bits for word & byte displacement # bits in...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
Q2. Consider a four-way set associative cache with a data size of 64 KB. The CPU...
Q2. Consider a four-way set associative cache with a data size of 64 KB. The CPU generates a 32-bit byte addressable memory address. Each memory word contains 4 bytes. The block size is 16 bytes. Show the logical partitioning of the memory address into byte offset, cache index, and tag components.
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
A (word, bit, block, byte) or (Sector, cache line, page, row) is the unit of data...
A (word, bit, block, byte) or (Sector, cache line, page, row) is the unit of data transferred between cache, memory and the processor. A common size for a block is (64, 16, 32, 4k, 512) (bytes, lines, words, bits)
32 bytes of memory. 16 bytes of 2-way setassociative cache, where blocks can go anywhere within...
32 bytes of memory. 16 bytes of 2-way setassociative cache, where blocks can go anywhere within the set. Block is 4 bytes, set in cache is two blocks. Populate memory starting with 0-9, then upper case letters. Hint- with full associativity in the set: each block has its own set of Tag bits in the cache. Memory is not organized by sets, though blocks get assigned to sets, and load in the cache per set. A) Complete: Bits in Address...
Problem 6. Suppose we have a computer with 32 megabytes of main memory, 256 bytes of...
Problem 6. Suppose we have a computer with 32 megabytes of main memory, 256 bytes of cache, and a block size of 16 bytes. For each configuration below, determine the memory address format, indicating the number of bits needed for each appropriate field (i.e. tag, block, set, offset). Show any relevant calculations. Direct cache mapping and memory is byte-addressable a) Direct cache mapping and memory is word-addressable with a word size of 16 bits b) c) 2-way set associative cache...
question 2 and 3 2. Determine how many sets of cache blocks will be there for...
question 2 and 3
2. Determine how many sets of cache blocks will be there for the following Cache memory size (in bytes) Direct Mapped Blocks Size (in bits) 32 64 218 2-way Set Associative Block Size (in bits) 32 64 A 2A6 [0.5 * 16 = 8] 4-way Set Associative Block Size (in bits) 32 64 SK 64K 256K 3. The physical memory address generated by a CPU is converted into cache memory addressing scheme using the following mapping...
This problem concerns a physical memory cache. Recall that m is the number of physical address...
This problem concerns a physical memory cache. Recall that m is the number of physical address bits, C is the cache size (number of bytes), B is the block size in bytes, E is the associativity, S is the number of cache sets, t is the number of tag bits, s is the number of set index bits, and b is the number of block offset bits. Suppose we have a cache with the following characteristics m = 32 C...
Question 6 For the following figure shows a hypothetical memory hierarchy going from a virtual address to L2 cache acce...
Question 6 For the following figure shows a hypothetical memory hierarchy going from a virtual address to L2 cache access. The page size is 8KB, the TLB is direct mapped with 128 entries. The L1 cache is a direct mapped 8 KB, and the L2 cache is 2MB and direct mapped. Both use 64 byte blocks. The virtual address is 64 bits and the physical address is 41 bits. For each block in the figure below, fill in the number...
1. A cache holds 64 words where each word is 4 bytes. Assume a 32 bit address. There are four different caches a. A direct-mapped cache with block size = 16 words b. 2-way set-associative cache with block size = 8 words c. 4-way set-associative cache with block size=4 words d. A fully associative cache with block size = 16 words. Complete the table for each cache. Cache a Cache be Cache Cache de 16 Number of bits needed for...
Question 3: Consider a 32-bit physical address memory system with block size 16 bytes and a 32 blocks direct mapped cache. The cache is initially empty. The following decimal memory addresses are referenced 1020, 1006, 1022, 5106, 994, and 2019 Map the addresses to cache blocks and indicate whether hit or miss. Note: You must use the hexadecimal approach in solving this question. You must also show the computations of dividing the memory address into tag bits, cache index bits,...
Problem 6. Suppose we have a computer with 32 megabytes of main memory, 256 bytes of cache, and a block size of 16 bytes. For each configuration below, determine the memory address format, indicating the number of bits needed for each appropriate field (i.e. tag, block, set, offset). Show any relevant calculations. Direct cache mapping and memory is byte-addressable a) Direct cache mapping and memory is word-addressable with a word size of 16 bits b) c) 2-way set associative cache...
question 2 and 3
2. Determine how many sets of cache blocks will be there for the following Cache memory size (in bytes) Direct Mapped Blocks Size (in bits) 32 64 218 2-way Set Associative Block Size (in bits) 32 64 A 2A6 [0.5 * 16 = 8] 4-way Set Associative Block Size (in bits) 32 64 SK 64K 256K 3. The physical memory address generated by a CPU is converted into cache memory addressing scheme using the following mapping...
Question 6 For the following figure shows a hypothetical memory hierarchy going from a virtual address to L2 cache access. The page size is 8KB, the TLB is direct mapped with 128 entries. The L1 cache is a direct mapped 8 KB, and the L2 cache is 2MB and direct mapped. Both use 64 byte blocks. The virtual address is 64 bits and the physical address is 41 bits. For each block in the figure below, fill in the number...
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