An archer shoots an arrow at a 75.0 m distant target; the bull
An archer shoots an arrow at a 75.0 m distant target; the bull
Homework Answers
a.)
I think that you can use the range equation to figure out the angle
(?):
R=[(Vo)^2*2Sin?]/g
Where
R=73.0m
Vo=36m/s
g=9.8m/s^2
?=?
Solve for ?:
73.0m=[(36m/s)^2*2Sin?]/(9.8m/s^2)
73.0m*9.8m/s^2=[(36m/s)^2*2Sin?]
715.4=1296*2Sin?
(715.4/1296)*1/2=Sin?
(0.552)*1/2=Sin?
Sin^-1(0.276)=?
?=16.02
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