Calculate λmax for blackbody radiation for the following.
(a) liquid helium (3.8 K)
(b) room temperature (293 K)
(c) a steel furnace (1200 K)
(d) a blue star (9200 K)
λmax*T= 2.89*10^-3 mK
λmax=2.89*10^-3 mK/3.8
=0.760*10^-3 m---a
b)λmax*T= 2.89*10^-3 mK
λmax= 2.89*10^-3 mK/293
=0.00986*10^-3 m--b
c)
λmax*T= 2.89*10^-3 mK
λmax= 2.89*10^-3 mK/1200
=0.0024*10^-3 m--c
d)
λmax*T= 2.89*10^-3 mK
λmax= 2.89*10^-3 mK/9200
=0.00031*10^-3 m
Calculate λmax for blackbody radiation for the following. (a) liquid helium (3.8 K) (b) room temperature...
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A small object with an opaque, diffuse surface at a temperature
of 500 K is suspended in a large furnace with walls at 2000 K.
Assume that the walls of the furnace provide a diffuse irradiation
to the object at a blackbody temperature equal to the furnace wall
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