4) Given the following information what is the p-value of the test? Using the p-value method would you reject or not reject the null hypothesis at a significance level of 0.05? (8 pts)
a) The test statistic for a right-tailed test is z = 0.55
b) The test statistic for a two-tailed test is z = 1.95
c) The test statistic in a left-tailed test is z = -1.72.
d) The test statistic for a two-tailed test is z = -1.63.
If p - value will be less than 0.05 then we will reject the null hypothesis. Hence,
a) p - value = P(z > 0.55) = 0.2912 > 0.05
Do not reject Ho
b) p - value = 2*P(z > 1.95) = 2*0.0256 = 0.0512 > 0.05
Do not reject Ho
c) p - value = P(z < -1.72) = 0.0427 < 0.05
Reject Ho
d) p - value = 2*P(z < -1.63) = 2*0.0516 = 0.1032 > 0.05
Do not reject Ho
4) Given the following information what is the p-value of the test? Using the p-value method...
Question 18 (4 points) Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a two-tailed test is z = -1.63. 1) 0.9484; fail to reject the null hypothesis 2) 0.1032; fail to reject the null hypothesis 3) 0.0516; fail to reject the null hypothesis 4) 0.0516; reject the null hypothesis
Provide an appropriate response. Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H o for the level of significance a. Two-tailed test z= 1.95 a = 0.05 0.0512; fail to reject Ho 0.0256; reject Ho 0.9744; fail to reject Ho 0.0512; reject Ho QUESTIO 8 points Save Answer Provide an appropriate response. Find the P-value for the hypothesis test with the standardized test statistic z. Decide whether to reject H o...
Use the given information to find the p-value. Use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). a. The test statistic in a right-tailed test is z = 1.00. b. The test statistic in a test with alternative hypothesis p 6= 5/7 is z = 2.05. c. The test statistic in a test with alternative hypothesis p < 2/3 in z = −0.45.
Question 7 3 pts Provide the following information: A. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. B. Find the p-value to within 3 decimal places. C. Using a significance level of a = 0.05, do we reject Ho or fail to reject Ho? The test statistic of z=0.20 is obtained when testing the claim that p 2 0.39. A. Tail: two, left or right B. P-value: C. Reject or Fail to Reject the null HTML Editora
Question 6 3 pts Provide the following information: A. Identify the hypothesis test as being two-tailed, left-tailed, or right-tailed. B. Find the p-value to within 3 decimal places. C. Using a significance level of a = 0.05, do we reject Ho or fail to reject Ho? The test statistic of z = -2.50 is obtained when testing the claim that p < 0.75. A. Tail: two, left or right B. P-value: C. Reject or Fail to Reject the null HTML...
How can I find a p-value when given a test statistic only with no df? I am preferably looking for a method with a TI-84 but will accept any answer, here is the question I am trying to answer: Use the given information to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is...
The value obtained for the test statistic, z, in a one-mean 2-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b). determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a two-tailed test is z= -1.42. The P-value is (Round to three cocimal places as...
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis).The test statistic in a right-tailed test is z=0.52. A. 0.6030; fail to reject the null hypothesis B. 0.3015; reject the null hypothesis C. 0.0195; reject the null hypothesis D. 0.3015; fail to reject the null hypothesis
Use the given information to find the p-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a right-tailed test is zequals=0.52.
Use the information given below to find the P-value. Also, use a 0.05 significance level and state the conclusion about the null hypothesis (reject the null hypothesis or fail to reject the null hypothesis). The test statistic in a left-tailed test is z= - 1.29. What is the P-value? P-value = (Round to four decimal places as needed.) p-p Find the value of the test statistic z using z pa n The claim that the proportion of peas with yellow...