Homework Answers
1. the III 3 is the carrier for disease - Tt (heterozygous)
2. the III 2 is normal - TT ( homozygous dominant)
the probability that their child will have Tay-Sachs which is the homozygous recessive disorder = tt
| T | t | |
| T | TT | Tt |
| T | TT | Tt |
so according to Punnett square
- the child will have Tay-Sachs ( tt) = 0 %
- the child with carrier = 50 %
- normal child = 50 %
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Please provide answers with explanations for these
questions.
1. Tay Sachs disease is an inherited disorder. Children who are born with Tay Sachs have progressive neurological problems and typically die before age 4. It is inherited in an autosomal recessive manner Below are pedigrees from two families where some members of a family have Tay Sachs disease. Neither Hillary nor Justin have Tay Sachs disease. If Hillary and Justin have a child, what is the chance this child will have...
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