For which reaction is AH°xn= AH? A) 2 H2(g) + O2(g) → 2 H,0(1) B) 2...
Please explain Data: C(graphite) + O2(g) => CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) => H2O(1) AH = -285.8 kJ CH3OH(1) + 3/202(9) A CO2(g) + 2H20(1) AH = -726.4 kJ Using the data above, calculate the enthalpy change for the reaction below. Reaction: C(graphite) + 2H2(g) + 1/2O2(g) => CH3OH(1) A. +238.7 kJ B.-238.7 kJ C. +548.3 kJ D.-548.3 kJ E. +904.5 kJ
Which of the following statements is/are correct? 1. ∆H° for the reaction C(diamond) + O2(g) → CO2(g) is the enthalpy of combustion of diamond. 2. ∆H° for the reaction C(graphite) + 1/2 O2(g) → CO(g) is the standard enthalpy of formation (∆Hf) of CO(g). 3. ∆H° for the reaction C(graphite) → C(diamond) is the standard enthalpy of formation (∆Hf) of diamond. A. all B. 2 only C. 1 and 2 only D. 1 and 3 only E. 2 and 3...
Given the following equations and AH' values: C(s) + O2(g) + CO2(g) AH = -393.5 kJ H2(g) + 1/2O2(g) - H20 (1) AH = -285.8 kJ 2C2H2 (8) + 5O2(g) + 4CO2(g) + 2H20 (1) AH'= -2598 kJ Determine the heat of reaction (in kJ) at 298 K for the reaction: 2C(s) + H2(8) C2H2 (8) 0-136.8 0-219.8 0-109.9 O-167.1 +226.2
Find AHrxn for: C2H2(g) → 2C(s) + H2(g) given the following information: C2H2(g) + 5/2 O2(g) → 2002(g) + H2O (1) AH° = -1291 kJ C(s) + O2(g) + CO2(g) AH° = -391 kJ H2(g) + 1/2O2(g) + H2O(1) AH° = -280 kJ kJ
Given that H2(g) + F2(g) → 2 HF(g) AH;xn = -546.6 kJ 2 H2(g) + O2(g) + 2H,0(1) AH;x= -571.6 kJ calculate the value of AHEX for 2F2(g) + 2 H20(1) + 4HF(g) + O2(8) AH
Which reaction is accompanied by an increase in entropy? A N2(g) + 3 H2(g) – 2 NH3(g) B. Ba(OH)2(s) + CO2(g) → BaCO3(s) + H2O(1) C. NH4NO2(s) – N2(g) + 2 H20(0) D.2 C2H2(g) + 5 O2(g) – 4 CO2(g) + 2 H2O(s) E. C8H16(1) + 12 O2(g) — 8 CO2(g) + 8 H 20(1)
calculate delta H for the reaction C(diamond)=C(graphite) given the following data C(diamond)+O2(g)=CO2(g) deltaH=-395.45kJ C(graphite)+O2(g)=CO2(g) delta H= 393.5kJ deltaH=
17. From the following heats of reaction, 2C (graphite) + H2 (g) → C2H2 (g) AH = 227 kJ/mole 6C (graphite) + 3H2 (g) → CH (1) AH = 49 kJ/mole calculate the heat for the reaction 3C2H2 (g) → C6H6 1) A. 632 kJ/mole B. -632 kJ/mole C. -178 kJ/mole D. 178 kJ/mole
AH = -727 kJ Given that CH3OH (1) + 3/2 O2 (g) → CO2 (g) + 2 H2O(1) CO(g) + 1/2O2 (g) → CO2 (9) CH3OH(1) → CH3OH(g) AH = -284 kJ AH = 38 kJ H20 (1)→ H20 (9) AH = 44 kJ what is AH, in kJ, for the reaction CH3OH (g) + O2(g) →CO (g) + 2 H2O (9)
2. Use the thermochemical equations shown below to determine the enthalpy for the reaction: (5 marks) C3H8(0) + 5O2(g) →3CO2 + 4 H2O) CO2 +Cgraphite) + O2 AH° = 221.6KJ H2(g) + 1/2O2(g) +H2O AH = -160.3KJ 3 C(graphite) + 4H2(g) →C3H8(9) AH = -58.5KJ 3. Use the thermochemical equations shown below to determine the enthalpy for the reaction: (5 marks) SO2(g) →S(8) + O2(9) H2S(g) + 3/202(g) → H2SO3(1) H2SO3(1)→ H2O +SO2(g) H2S(9)+ 1/2O2(0)+S(8) + H2O) AH = -306KJ...