Question

4. The kinetic theory of an ideal gas takes into account not only translational motion of atoms or molecules but also, for diatomic and polyatomic gases. vibration and rotation. Will the temperature increase from a given amount of energy being supplied to a monoatomic gas differ from the temperature increase due to the same amount of energy being supplied to a diatomic gas? Explain.

Answer 1

Let us according to equputition the average kinematic energy associated with each degree of freedom can be exp - ressed as below k = 1/2 KBT 6 Here , ke — Boltzmann constant. T - Absolute temperature Monatomic gases have only translational motion. Hence the no. of degrees of treedom is there. Hence the average kinetic Energy associated with monatomic km = 36 kB Tm) : 5 Kg Im @ Diatomic gases have translational as well as rotational motion. Hence the total no. of degrees of freedom is g. gogos و حق with In the se 5 degrees of freedom, there are associated translational motion and the remaining two degrees associated with Yotational motion. are the average ke associated with diatomic gases is d = (3+2) - Keld = 5 kBId ©

up the same amount of Energy is supplied to both monatomic and diatomic gases, then I kd = km 틀성: 홀 FeTm Then , To = 3 / 2 kB Tm f H5 k Td = 3 Tm * Thus, it can be concluded more in case of mona tomic that temperature increase aas compared to the di- is same amount of Energy being - atomic - lied to gases the supp- when diatoic the gas. In this reason, the temperatwe is a measure of the translational motion of atoms Cor). mode cules and some part of the supplied Energy is used for the rotational motion of a diatomic gas. the position of the pt, ushere intensity of -> the 70 find dectric field is 2000 : Sol: The Situation can be visualized as +39 --- ---- 9. A B -- E-V >4 10 cm

We assume that at pt A The Electric field is zero. At . pt A is at The electric distance a from B. field due to charge og at pt A is And the electric field due to charge +39 at pt a eis +39 = 1 39 4 TT E (10 The Sum cor these two electric field must be geso? E + E = 0 4 +34 when compare top ) -- > Cioras to => che per 1) 32" - (10+ 0 32" - 100 + 201 ta 209–204 - 100 =0 -10- 50 =0

x= 13.66 cm and a = -3.66 cm. wwe are sotving for a +re value or a So, the position of the pt in +13,66 cm from charge away from the charge. the .-ve