Question

--->Found that 2.64(10^6) kg of coal was consumed.

Day 19 and 20 Homework: Heat engines, refrigerators, and heat pum... Saved 4. Required information Part 2 of 2 NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part A coal-burning steam power plant produces a net power of 300 MW with an overall thermal efficiency of 35 percent. The actual gravimetric air-fuel ratio in the furnace is calculated to be 12 kg air/kg fuel. The heating value of the coal is 28,000 kJ/kg. 10 points Determine the rate of air flowing through the furnace. eBook The rate of air flowing through the furnace is kg/s. Hint

Answer 1

Given data; ninet 300 MW The net power 35% =0.35 overall efficiency no 12 kg air/kg fuel Airfuel AF = rectio 9 cool Heating value - 28000 kJ/kg amount of coal consumed moal = 2-640106 kg The rate of air howing through the furmance mcoal mcoel st The rate of coal consumed 6 incoal 2:64 X10 3600x24 = 30.556 kg/s ž 31 kg/s (Take: amount of coal consumed during 24-hour period ) The rate of air flowing mais - CAF) mwal - = -372 kg/s 12% 31 mair = 372 kg/s