ESE2402 Homework G-1 G-2 150 MW V-13.8kV V1-15.0kV 2 TR-I TR-2 30 MVAr S0 MW Line-...
Problem #1 Part I (50 points) Consider the following one-line diagram of a three-phase power system. Assume that the system has the following base quantities: S3 100 MVA, and VbaselL 38 kV at the generator side. The rated line-to-line terminal voltage of the generator (BUS 1) is 38 kV. A single-circuit three-phase transposed overhead line composed by one ACSR Partridge conductor per phase with vertical configuration. The transmission line length is 50 km and the distance between phases a-b, b-c...
The one-line diagram of a power system is given below. Draw the impedance diagram of the given system in per unit by selecting a common base of 200 MVA and 160kV on bus 4 for fault analysis. (20pts) 60 km 40 km Grounded Infinite Bus 4 6 5 60 km 60 km 60 km 80 km G BE 60 km 1 Tr N 3 G: 150 MVA, 10.8kV, X®G= 0.12 pu, Xa=0.8 pu Tr: 160 MVA Ratio: 11.2kV/154 kV Xtr=0.12...
Problem 2 (50 points): The generator in the figure generates and delivers 150 MW to the power system below. At steady state the generator regulates the generating station voltage (bus 1) to pu. The system voltage at bus 3 is 1.05 pu. 1. Compute the internal voltage and rotor angle of the generator under the above conditions. 2. The fault sequence for a solid three-phase fault on any of the line circuits consists of a delayed tripping of both circuit...
The six-bus system shown in Figure 1 will be simulated using MATLAB. Transmission line data and bus data are given in Tables 1 and 2 respectively. The transmission line data are calculated on 100 MVA base and 230 (line-to-line) kV base for generator. Tasks: 1. Determine the network admittance matrix Y 2. Find the load flow solution using Gauss-Seidel/Newton Raphson method until first iteration by manual calculation. Use Maltab software to solve power flow problem using Gauss-Seidel method. Find the...
The ratings of the components shown in the one-line diagram are G1: 25 MVA, 13.8 kV, x-0.15 pu G2:15MVA, 13 kV, x = 0.1 5 pu. TI : 25 MVA, 13.2/69 kV, x-0. I 1 pu T2: 25 MVA, 69/13.2 kV,x-0.220 pu Transmission line: j65 ohms/pha bus 2 BE 165Ω ISMVA e ratings of generator 1 as base valu 25MVA 13.8 kV 1 5% 69113.2 kV13kV 1 1% 13.2169k 1 1% 1- Draw the reactance diagram. 2- Find the Y-bus...
A single line diagram of a power system is shown in Fig. 2. The system data with equipment ratings and assumed sequence reactances are given the following table. The neutrals of the generator and A-Y transformers are solidly grounded. The motor neutral is grounded through a reactance Xn 0.05 per unit on the motor base. Assume that Pre-fault voltage is takin as VF-1.0 ,0° per unit and Pre- fault load current and Δ-Y transformer phase shift are neglected In the...
Answer part D
The single line diagram of a power network is shown in the figure. Bus#1 is a slack bus. The scheduled powers for bus#2 and bus#3 are given. The impedances shown in the figure are all in per-unit considering a power base of 100 MVA. 30 400 MW 320 MVAr Slack V-140 j0.0125 jo.0s 00 MW 270 MVAr A. Use the Gauss Seidel technique to determine voltages at bus#2 & bus#3. (Start with an initial guess 140 for...
Problem #2 An industrial system bus is fed from an infinite bus thru a 150 MVA, 115kV/38kV, X=5% substation connected to a 75 MVA, 38kV/13.8kV, X-6.5% substation. A 25 MW, 13.8 kV, pf=.85, 3-phase, x=16% diesel generator is also connected to the industrial system bus. Several feeders are connected to the 38kV bus. If a fault occurs in one of such feeders, plot sag voltage at the 13.8kV bus vs. distance to fault with and without the generator contribution. The...
Problem #2: (40 points) The three-phase power and line- given below line ratings of the electric power system shown are G:60 MVA, 20 kV, X = 9% Tr 50 MVA. 20/200 kV.x 1096 T2: 50 MVA, 20020 kV, X 10% M: 43.2 MVA, 18 kV, X 8% Line: 200 kV, Z 120+j200 Ti Line 00-MVA 1. Draw an impedance diagram showing all impedances in per-unit on a1 2. The motor is drawing 40 MVA, 0.8 power factor lagging at a...
3) The single-line diagram of a three-phase power system is shown in Fig. 1. Equipment ratings are given as follows: G1 1,000 MVA, 15.0 kV, 20.18, o 0.07 pu G2 : 1,000 MVA. 15.0 kV, 攻=エ1 =エ2 = 0.20, ro = 0.10 pu G3 : 500 MVA, 13.8 kV. 1" = 띠 z2 = 0.15, zo 0.05 pu G4 : 750 MVA, 13.8 kV. ェd =ェ1 = 0.30, T2 = 0.40 ro = 0.10 pu Ti : 1,000 MVA. 15.0Δ/765Y...