Homework Answers
#include<stdio.h>
int main() {
int a = 55;
int *pa = &a;
int **ppa = &pa;
printf("The content of a is %d\n",
a);
printf("The address of a is %p\n",
&a);
printf("The content of pa is %p\n",
pa);
printf("The address of pa is %p\n",
&pa);
printf("The dereferenced value of pa is %d\n",
*pa);
printf("The content of ppa is %p\n",
ppa);
printf("The address of ppa is %p\n",
&ppa);
printf("The dereferenced value of ppa is %p\n",
*ppa);
printf("The content of a through ppa is %d\n",
**ppa);
return 0;
}
OUTPUT
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Read the following code and fill the following blanks (no space is allowed): #include <stdio.h> int...
#include<stdio.h> #include <stdlib.h> void read(struct Employee *e); struct Employee { int id; int age; }; int...
#include<stdio.h> #include <stdlib.h> void read(struct Employee *e); struct Employee { int id; int age; }; int main(){ struct Employee e; read(&e); } void read(struct Employee *e){ int a,b; printf("Enter the id employee\n"); scanf("%d",&a); printf("Enter the age employee\n"); scanf("%d",&b); e->id=a; e->age=b; } Question: Declare a pointer variable of type Employee and place the address of the variable created in the above problem in that pointer variable.
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What is the functionality of the following code? #include #include mainO <stdio.h> <unistd.h> int i,j; j-0:...
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#include <stdio.h> #include <stdint.h> int Pointers_main (int arge, char *argv[]) int16_t a; // Declare a int32_t...
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In C
Code provided:
#include <stdio.h>
int recursive_sequence(int n)
{
//type your code here
}
int main()
{
int number;
scanf("%d", &number);
printf("recursive_sequence(%d) = %d",number,
recursive_sequence(number));
return 0;
}
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In C
Code provided:
#include <stdio.h>
int recursive_sequence(int n)
{
//type your code here
}
int main()
{
int number;
scanf("%d", &number);
printf("recursive_sequence(%d) = %d",number,
recursive_sequence(number));
return 0;
}
The nth term in a sequence of numbers called recursive_sequence can be defined as follows: • recursive_sequence(0) = 0 • recursive_sequence(1) = 1 If n is greater than 1, then recursive_sequence(n) = 2* recursive_sequence(n - 2) + recursive_sequence(n-1) The first 6 terms in this sequence are: 0,1, 1, 3, 5, 11...
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