Part II: Let Me Inn (20 points)
You are the manager of the Let Me Inn. A travel agent has sent you
a list of reservations that can be accommodated
by the hotel. Your primary job is to send him back the total cost
of the reservations. To make sure your hotel runs
properly, you also will keep track of how much money you have made
from each type of room (Normal, Double,
King, Suite).
Complete the function hotel manager which takes arguments in the
following order:
1. room prices: A dictionary that maps a type of room (a string) to
the price of the room (an integer).
2. room counts: A dictionary that maps a type of room (a string) to
the number of available rooms of that
type (an integer).
3. reservations: A list of sub-lists wherein the first element of a
sub-list contains the type of room being
reserved, and the second element is the desired count of rooms of
that type. For example, the sub-list
[’King’, 3] would indicate that 3 King rooms are desired.
The function iterates over the reservations list, extracting the
room type and room count of each reservation.
Room types can appear multiple times in the list. Then, the
function looks up the price of the desired room
using the room prices dictionary and determines what it would cost
to reserve the desired number of rooms.
You may assume that the room type in the reservation always has a
corresponding price in room prices and a
corresponding count in room counts.
If there are enough available rooms to accept the reservation, the
function (1) updates the total income generated
by the reservation, (2) updates room counts to reflect that fewer
rooms are now available, and (3) updates a
dictionary that tracks how much income was generated by each type
of room. As an example, suppose that a King
room costs $200 per night and 3 have such rooms been successfully
reserved. Suppose also that we have created a
dictionary called room incomes to store the income generated by
each room type. In this example, the function
would add 600 both to room incomes[’King’] and to the total income
generated. It would also subtract 3
from room counts[’King’].
If a certain reservation in reservations list cannot be
accommodated due to a shortage of rooms, the function
skips over that reservation and moves on to the next one in the
list.
At the end, the function returns two values in a tuple: the total
income generated by the accepted reservations,
followed by the updated room incomes dictionary.
Examples:
Function Call Return Values
hotel manager({’Normal’: 70, ’Double’: 105,
’King’: 195, ’Suite’: 249}, {’Normal’: 13,
’Double’: 9, ’King’: 5, ’Suite’: 3}, [[’Suite’,
1], [’King’, 3], [’Double’, 6], [’King’, 5],
[’King’, 3], [’King’, 5]])
(1464, {’Suite’:
249, ’King’: 585,
’Double’: 630})
hotel manager({’Normal’: 79, ’Double’: 101,
’King’: 190, ’Suite’: 270}, {’Normal’: 12,
’Double’: 7, ’King’: 7, ’Suite’: 3}, [[’King’,
4], [’Double’, 7], [’Suite’, 2]])
(2007, {’King’: 760,
’Double’: 707,
’Suite’: 540})
hotel manager({’Normal’: 60, ’Double’: 128,
’King’: 178, ’Suite’: 226}, {’Normal’: 11,
’Double’: 8, ’King’: 5, ’Suite’: 4}, [[’Suite’,
1], [’King’, 5], [’Suite’, 2], [’Normal’, 9]])
(2108, {’Suite’:
678, ’King’: 890,
’Normal’: 540})
hotel manager({’Normal’: 78, ’Double’: 106,
’King’: 193, ’Suite’: 239}, {’Normal’: 12,
’Double’: 10, ’King’: 6, ’Suite’: 3},
[[’Suite’, 3], [’Double’, 5], [’King’, 3],
[’Suite’, 2], [’King’, 4], [’Double’, 5],
[’Double’, 7]])
(2356, {’Suite’: 717,
’Double’: 1060,
’King’: 579})
hotel manager({’Normal’: 97, ’Double’: 144,
’King’: 185, ’Suite’: 242}, {’Normal’:
11, ’Double’: 7, ’King’: 7, ’Suite’: 4},
[[’Normal’, 10], [’King’, 3], [’King’, 4],
[’King’, 4]])
(2265, {’Normal’:
970, ’King’: 1295})
hotel manager({’Normal’: 73, ’Double’: 145,
’King’: 160, ’Suite’: 295}, {’Normal’: 11,
’Double’: 8, ’King’: 7, ’Suite’: 3}, [[’King’,
5], [’Double’, 5], [’Suite’, 1], [’Double’, 6],
[’Double’, 7], [’Suite’, 3]])
(1820, {’King’: 800,
’Double’: 725,
’Suite’: 295})
hotel manager({’Normal’: 73, ’Double’: 145,
’King’: 162, ’Suite’: 215}, {’Normal’:
11, ’Double’: 7, ’King’: 6, ’Suite’: 4},
[[’Normal’, 11], [’Normal’, 11], [’Suite’, 1],
[’Suite’, 1], [’Double’, 7], [’Double’, 5],
[’Suite’, 0]])
(2248, {’Normal’:
803, ’Suite’: 430,
’Double’: 1015})
hotel manager({’Normal’: 62, ’Double’: 100,
’King’: 164, ’Suite’: 252}, {’Normal’: 0,
’Double’: 0, ’King’: 0, ’Suite’: 0}, [])
(0, {})
hotel manager({’Normal’: 60, ’Double’: 124,
’King’: 155, ’Suite’: 296}, {’Normal’: 12,
’Double’: 8, ’King’: 5, ’Suite’: 4}, [])
(0, {})
hotel manager({’Normal’: 60, ’Double’: 107,
’King’: 155, ’Suite’: 299}, {’Normal’: 0,
’Double’: 0, ’King’: 0, ’Suite’: 0}, [])
(0, {})
In python thank you
def hotel_manager(room_prices, room_counts, reservation_list): # This dictionary store earned money from each room type # Key is room type and value is income income_list = {} # Total money earned total_income = 0 # For each sub list in reservation list for sublist in reservation_list: room_type = sublist[0] # sublist[0] contains type of room to be reserved num_rooms = sublist[1] # sublist[1] contains cost of room to be reserved # Check if number of room type to be reserved are available or not # If yes, calculate the total cost incurred # Else, skip reservation if room_counts[room_type] >= num_rooms: # cost = number of rooms to be reserved * price of that room cost = (num_rooms * room_prices[room_type]) # If type of room is already present in dictionary # Update dictionary by updating income generated for current room_type # Else, add new room_type in dictionary if room_type in income_list.keys(): income_list[room_type] = income_list[room_type] + cost else: income_list[room_type] = cost # Increment total income by adding cost to it total_income += cost # Update count in room_counts dictionary room_counts[room_type] -= num_rooms # Return total_income and income_list return total_income, income_list if __name__ == '__main__': income = hotel_manager({'Normal': 70, 'Double': 105, 'King': 195, 'Suite': 249}, {'Normal': 13, 'Double': 9, 'King': 5, 'Suite': 3}, [['Suite', 1], ['King', 3], ['Double', 6], ['King', 5], ['King', 3], ['King', 5]]) print(income) income = hotel_manager({'Normal': 79, 'Double': 101, 'King': 190, 'Suite': 270}, {'Normal': 12, 'Double': 7, 'King': 7, 'Suite': 3}, [['King', 4], ['Double', 7], ['Suite', 2]]) print(income) income = hotel_manager({'Normal': 60, 'Double': 128, 'King': 178, 'Suite': 226}, {'Normal': 11, 'Double': 8, 'King': 5, 'Suite': 4}, [['Suite', 1], ['King', 5], ['Suite', 2], ['Normal', 9]]) print(income) income = hotel_manager({'Normal': 78, 'Double': 106, 'King': 193, 'Suite': 239}, {'Normal': 12, 'Double': 10, 'King': 6, 'Suite': 3}, [['Suite', 3], ['Double', 5], ['King', 3],['Suite', 2], ['King', 4], ['Double', 5],['Double', 7]]) print(income) income = hotel_manager({'Normal': 97, 'Double': 144, 'King': 185, 'Suite': 242}, {'Normal': 11, 'Double': 7, 'King': 7, 'Suite': 4}, [['Normal', 10], ['King', 3], ['King', 4],['King', 4]]) print(income) income = hotel_manager({'Normal': 73, 'Double': 145, 'King': 160, 'Suite': 295}, {'Normal': 11, 'Double': 8, 'King': 7, 'Suite': 3}, [['King',5], ['Double', 5], ['Suite', 1], ['Double', 6],['Double', 7], ['Suite', 3]]) print(income) income = hotel_manager({'Normal': 73, 'Double': 145, 'King': 162, 'Suite': 215}, {'Normal': 11, 'Double': 7, 'King': 6, 'Suite': 4}, [['Normal', 11], ['Normal', 11], ['Suite', 1],['Suite', 1], ['Double', 7], ['Double', 5], ['Suite', 0]]) print(income) income = hotel_manager({'Normal': 62, 'Double': 100, 'King': 164, 'Suite': 252}, {'Normal': 0, 'Double': 0, 'King': 0, 'Suite': 0}, []) print(income) income = hotel_manager({'Normal': 60, 'Double': 124, 'King': 155, 'Suite': 296}, {'Normal': 12, 'Double': 8, 'King': 5, 'Suite': 4}, []) print(income) income = hotel_manager({'Normal': 60, 'Double': 107, 'King': 155, 'Suite': 299}, {'Normal': 0, 'Double': 0, 'King': 0, 'Suite': 0}, []) print(income)
SCREENSHOT
OUTPUT
Part II: Let Me Inn (20 points) You are the manager of the Let Me Inn....
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