1. 2. 3. H3C CH2CH3 0% CH3 CH2CH(CH32 Hc CH2CH2CH Which of the alkenes above is...
H3C CH2CH3 13 H2C=C CH2CH(CH3)2 H2C=C н H2CH CH2CH2CH3 Which of the alkenes above is the least stable (highest in energy)? Which is the most stable (lowest in energy)? ' Submit Answer Retry Entire Group 2 more group attempts remaining [Review Topics) . . References ECHCH3 CH=CH2 CH3 Which of the alkenes above is the least stable (highest in energy)?_ Which is the most stable (lowest in energy)? Submit Answer Retry Entire Group 2 more group attempts remaining
H2C CH2CH3 CH3 crc CH2CH(CH3)2 H2C=C TEH H2C=C CH2CH2CH3 HzC Which of the alkenes above is the least stable (highest in energy)? Which is the most stable (lowest in energy)? _ Submit Answer Retry Entire Group 2 more group attempts remaining [Review Topics (References CHCH3 CH=CH2 -СН3 Which of the alkenes above is the least stable (highest in energy)? Which is the most stable (lowest in energy)? _ Submit Answer Retry Entire Group 2 more group attempts remaining eg
TRetetences Provide an IUPAC name for each of the compounds shown. (Specify (EY(Z) stereochemistry, if relevant for straight chain alkenes only. Pay attention to commas, dashes, etc.) CH2CH3 CH₃ CH2CH3 CH3CH2CH2 c= H3CH2CH2CH Submit Answer Try Another Version 10 item attempts remaining ipt Draw the structure of (E)-2,3,5-trimethyl-3-hexene. 1 pt 1pt . Consider E/Z stereochemistry of alkenes. • You do not have to explicitly draw H atoms. 1pt 1 pt co-TY,000- Submit Answer T ry Another W on 10 men...
H3 C H2Br Br2, H30* HC X CH3 HzC CH3 H3C CH3 Aldehydes and ketones can be halogenated at their a-position by reaction with Cl, Br, or 12, under acidic conditions. Using Br2 under acidic conditions, an intermediate enol is formed which adds bromine at the a-position. The reaction stops after the addition of one bromine because the electron-withdrawing halogen decreases the basicity of the carbonyl oxygen, making the protonation less favorable. Not started curved arrows to show the movement...
For the reaction below: H3C-CH3 12 2 HC-1 a. Estimate the gas phase enthalpy change using bond dissociation enthalpies from the OWL Table Reference, not data from your text. Click the References button and then click the Tables link on the drop-down that appears. Include algebraic sign and units. b. Is the reaction exothermic or endothermic? c. Is the reaction likely to proceed spontaneously in the direction written? Submit Answer Retry Entire Group more group attempt remaining
(References) Provide an IUPAC name for each of the compounds shown. (Specify (E) (Z) stereochemistry, if relevant for straight chain alkenes only. Pay attention to commas, dashes, etc.) CIH,C CHCI C=C н H CH(CH3)2 H2C сна Submit Relry Entire Group 7 more group attempts remaining Provide an IUPAC name for each of the compounds shown (Specify (E) (Z) stereochemistry, if relevant, for straight chain alkenes only. Pay attention to commas, dashes, etc.) нс сн; C=C H3C-CH HC-CH3 сна CH3 CH3...
For the gas phase isomerization of isopropenyl allyl ether, CH2=C(CH3)-O-CH2CH=CH2– CH3COCH2CH2CH=CH2 the rate constant has been determined at several temperatures. When In k in sis plotted against the reciprocal of the Kelvin temperature, the resulting linear plot has a slope of -1.48x104 K and a y-intercept of 26.0. The activation energy for the gas phase isomerization of isopropenyl allyl ether is kJ/mol. Submit Answer Retry Entire Group 8 more group attempts remaining For the gas phase decomposition of isobutyl bromide,...
Which of the following reactions will produce the molecule shown below? CH3(CH2)3–0–—CH, CH3 CHCH2)3 + HOẠC–CH2CH, CH2CH2)3-0–CH + H2C-CH3 CH3 (CH2)3-OH + HO—C—CH2CH3 CH3(CH2)3-OH + HC-CH2CH3
Rank the substituents shown below in order of Cahn-Ingold-Prelog priorities (1 = highest priority group, 4 = lowest priority group). -C(CH3)3 -CH(CH3)2 -CH3 -CH2CH3 Submit Answer Retry Entire Group 1 more group attempt remaining
15) The most stable conformation of 3-bromo-2-methylpentane, viewed through the C-2-C-3 bond (i.e., C-2 in the front, C-3 in the back) Br CH3 CH 3 CH3 H2CH H3C CH(CH3)2 CH3 CH3 CH3 CH2CH3 H2CH3 IV a) I b) II c) III d) IV e) V 15) The most stable conformation of 3-bromo-2-methylpentane, viewed through the C-2-C-3 bond (i.e., C-2 in the front, C-3 in the back) Br CH3 CH 3 CH3 H2CH H3C CH(CH3)2 CH3 CH3 CH3 CH2CH3 H2CH3 IV...