Homework Answers
Use Ka1 to find the first dissociation.
HOOCCX2COOH(aq) -> HOOCCX2COO-(aq) + H+(aq)
Initial. 0.127 0. 0
Equilibrium 0.127-x x x
Using equation for equilibrium constant
Ka1 = x.x/ (0.127-x)
0.0677= x2/(0.127-x)
Solving for x we get,
x = 0.065M
Now for the second step calculate x using Ka2 similarly
HOOCCX2COO-(aq) -> -COOCX2COO-(aq) + H+(aq)
intial 0.065 0 0
at equilibrium 0.065-x x. x
so, Ka2 = x.x/(0.065-x)
0.0348= x2/(0.065-x)
Solve the quadratic equation for x and you will get the value of x as 0.033M.
Thus, equilibrium concentration for HOOCCX2COO- is (0.065-0.033)= 0.032M
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