Homework Answers
It is clear from the diagram that
The image is real, larger and inverted.
So, the correct answer is
The image is a larger image with inverted orientation.
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Focus Object Region 1 Region 2 Reg on 3 The image is a virtual image on...
Focus Object Region 1 Region 2 Region 3 If an object is located in region 1,...
Focus Object Region 1 Region 2 Region 3 If an object is located in region 1, then answer the following questions about the image which is formed with a converging lens. Please draw the ray diagram to visualize the problem. _ side as the object. The image is located on the __ Submit Answer Tries 0/2 What is the image type? Submit Answer Tries 0/2 __than the object. The image size is Tries 0/2 Submit Answer What is the image...
Object in front of a convex mirror Points:3 An object is placed 14.5 cm in front...
Object in front of a convex mirror Points:3 An object is placed 14.5 cm in front of a convex mirror that has a focal length of -24.5 cm. Determine the location of the image. Submit Answer Tries 0/12 What is the magnification? Submit Answer Tries 0/12 In this example the image is ... O Virtual and upright. O Real and upright. O Virtual and inverted. O Real and inverted. Submit Answer Tries 0/12 e Post Discussion Send Feedback
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same...
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
An object is placed 13,.6 cm in front of a concave mirror that has a focal...
An object is placed 13,.6 cm in front of a concave mirror that has a focal length of 24.0 cm. Determine the location of the image. You are correct. Previous Tries 3.14x101 cm What is the magnification of the object discussed above? 2.31 You are correct. Previlous, Tries In this example the image is o Real and upright. Virtual and inverted. Real and inverted Virtual and upright. Tries 1/2 Previous Tries らSend Feedback
Starting with a real object, answer the following statements (True or False) about the image formed...
Starting with a real object, answer the following statements (True or False) about the image formed by a single lens? B A converging lens can produce a virtual, upright, enlarged image. e A diverging lens can produce a real, inverted, reduced image. A diverging lens always produces a virtual, upright, reduced image. False B A converging lens cannot a A converging lens can never produce a virtual, upright, reduced image. Suggestion: Make a table or a set of drawings showing...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
An object is placed 24.1 cm in front of a convex mirror of focal length 50...
An object is placed 24.1 cm in front of a convex mirror of focal length 50 cm. Note: Do convex mirrors have a positive or negative focal length? What is its image position? Answer in units of cm. The magnification of the image in the previ- ous question is: With the arrangement discussed above, the image is: 1. virtual, inverted, smaller than object 2. real, erect, smaller than object 3. real, inverted, bigger than object 4. real, erect, bigger than...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
is a) in front or behind the mirror is b)virtual and upright or real and inverted...
is a) in front or behind the mirror is b)virtual and
upright or real and inverted
24-9,10 Convex Mirror Due in 13 hours, 2 minutes A pink eraser is 23.2 mm tall and 11.6 em in front of (and on the axis of) a convex mirror. The mirror has a focal length whose magnitude is 26.1 cm. (a) Where is the image of the eraser? (Give the magnitude and direction of the image ocation. Submit Answer Tries 0/15 (b) What...
Focus Object Region 1 Region 2 Region 3 If an object is located in region 1, then answer the following questions about the image which is formed with a converging lens. Please draw the ray diagram to visualize the problem. _ side as the object. The image is located on the __ Submit Answer Tries 0/2 What is the image type? Submit Answer Tries 0/2 __than the object. The image size is Tries 0/2 Submit Answer What is the image...
Object in front of a convex mirror Points:3 An object is placed 14.5 cm in front of a convex mirror that has a focal length of -24.5 cm. Determine the location of the image. Submit Answer Tries 0/12 What is the magnification? Submit Answer Tries 0/12 In this example the image is ... O Virtual and upright. O Real and upright. O Virtual and inverted. O Real and inverted. Submit Answer Tries 0/12 e Post Discussion Send Feedback
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O inverted, diverging, positive, real upright, converging, positive, virtual inverted, converging, positive, virtual upright, converging, positive, real upright, converging, negative, virtual upright, converging, negative, real inverted, converging, positive, real O inverted, diverging, negative, real
An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) O upright, converging, positive, virtual O inverted, converging, positive, real inverted, diverging, negative, real O upright, converging, negative, virtual O inverted, diverging, positive, real O inverted, converging, positive, virtual O upright, converging, positive, real O...
An object is placed 13,.6 cm in front of a concave mirror that has a focal length of 24.0 cm. Determine the location of the image. You are correct. Previous Tries 3.14x101 cm What is the magnification of the object discussed above? 2.31 You are correct. Previlous, Tries In this example the image is o Real and upright. Virtual and inverted. Real and inverted Virtual and upright. Tries 1/2 Previous Tries らSend Feedback
Starting with a real object, answer the following statements (True or False) about the image formed by a single lens? B A converging lens can produce a virtual, upright, enlarged image. e A diverging lens can produce a real, inverted, reduced image. A diverging lens always produces a virtual, upright, reduced image. False B A converging lens cannot a A converging lens can never produce a virtual, upright, reduced image. Suggestion: Make a table or a set of drawings showing...
Question 18 (8 points) An object is placed 50.0cm in front of a lens. The image forms on the same side of the lens and is larger than the object. The image is (upright or inverted), the lens is (converging/diverging), image distance is (positive/negative), the image is (real, virtual) upright, converging, negative, real inverted, converging, positive, virtual upright, converging, negative, virtual upright, converging, positive, virtual upright, converging, positive, real O inverted, converging, positive, real inverted, diverging, positive, real inverted, diverging,...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
is a) in front or behind the mirror is b)virtual and
upright or real and inverted
24-9,10 Convex Mirror Due in 13 hours, 2 minutes A pink eraser is 23.2 mm tall and 11.6 em in front of (and on the axis of) a convex mirror. The mirror has a focal length whose magnitude is 26.1 cm. (a) Where is the image of the eraser? (Give the magnitude and direction of the image ocation. Submit Answer Tries 0/15 (b) What...
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