Question

In flies, assume black (B) is dominant and green (b) is recessive for abdomen color, a is dominant and bent the same chromosome. If single mutants for each of these genes (green abdomen x are crossed with one another, and you then numbers of each phenotype: nd straight (3 (s) is recessive for antenna shape. Assume also that these genes are found on bent antenna) testcross the resulting offspring, you get the following black, straight green, bent black, bent green, straight 337 364 What is the map distance between B and S? You must show and clearly label ALL work to receive credit.
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Answer #1

I have solved the above question in the picture below, so please take a look.

green, straight 36 fnd tha kecombination to 4ind Ind finally moup dis tamce betweenn ene Kecombi nation. No-o- recombinant, 100- 大 Totalohespmin 17 112 337 +361 16-0 一一3.974 730 3.97 94 the recombination 5o that gemes are the tenden be together halways ニー牛 recombinathon Noro).-Map olutarn co So Mop distance Joctween Band s is 3172 map units

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