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QUESTION 4 For the Circuit shown below. Find the Collector Current Vcc = 12 V Rp = 500 ko Rc = 4 k22 + ß= ? VCE = 3 V VBE 2.2
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Answer #1

Giver Circuit 9 Vcc= 12v Ro=4K2. 2 500 K2 Ic L BY VCE = 3V → from the Circuit Emitter is directly Connected to ground. So Ve=please upvote

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