Question

A block of mass kg is on a table and attached to a block of mass m2 4 kg by a massless string The of friction is table and m. The system is released from r After m2 coefficient 0.28 the falls 1.5 m, what is the speed of m2? m1
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Answer #1

Here ,

let the speed of the blocks is m1 and m2 is v

Using conservation of energy

0.50 * 3 * v^2 + 0.50 * 4 * v^2 = 4 * 9.8 * 1.50

solving for v

v = 4.1 m/s

the speed of the boxes m1 and m2 is 4.1 m/s

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