Use the information contained below to compress one time unit per move using the least cost method. Reduce the schedule until you reach the crash point of the network. For each move identify what activity(ies) was crashed and the adjusted total cost. (i.e., Calculate the minimum direct cost when project is finished in 13 days, 12 days, 11 days, as well as 10 days.)
Note: Choose B instead of C and E (equal costs) because it is usually smarter to crash early rather than late AND one activity instead of two activities
Summary
Step | Duration | Activity rashed (days crash) | Direct cost |
0 | 13 | - | 1000 |
1 | 12 | D(1) | 1040 |
2 | 11 | B(1) | 1140 |
3 | 10 | C(1), E(1) | 1240 |
Use the information contained below to compress one time unit per move using the least cost...
Use the information contained below to compress one time unit per move using the least cost method. Reduce the schedule until you reach the crash point of the network. For each move identify what activity(ies) was crashed and the adjusted total cost. (i.e., Calculate the minimum direct cost when project is finished in 13 days, 12 days, 11 days, as well as 10 days.)Note: Choose B instead of C and E (equal costs) because it is usually smarter to crash...
Use the information below to compress one-time unit per move using the least cost method. Reduce the schedule until you reach the crash point or the best cost value for this network. For each move identify what activity(s) should be crashed and the adjusted total cost. Total direct cost is $1000, total indirect cost is $800 and each time-unit reduction (cost gain) is $50. Activity Crash Cost per unit-time) Normal Normal Maximum time cost Crash Time 100 150 200 200...
Chapter 9 Reducing Project Durarion 327 7. Use the information contained below to compress one time unit per move using the least cost method. Assume the total indirect cost for the project is $2.000 and there is a savings of $100 per time unit reduced. Calculate the total direct, indirect, an graph. What is the optimum cost-time schedule for the project? Note: The correct normal project duration and total direct cost are provi ded. Normal Cost 200 1000 800 1000...
Question 6 - 8 Activity Depends on А B C D E F G A A А B C,D D, E, F Duration (Days) Normal Crash 5 4 7 5 8 5 11 8 6 4 4 3 7 5 Cost ($) Normal Crash 500 620 350 500 800 920 1000 1300 600 750 420 500 700 1000 6. Draw the node network for the above project using the following template. For each activity, show the computed value of early...
Problem #3 (25 points) For the construction project whose network diagram is shown below, a time-cost optimization procedure is required to determine the shortest duration and its corresponding lowest cost. Activity ID ES Darwin EF LS UF 1. Fill in values for the normal cost and crashed cost in the table below. Activities A and B already have costs associated with them. For activities through I do not use the same costs for any activity 2. Calculate the slope and...
TYPE: A CRAMOCerat Managmenti Sume 20t9 2 JCh. 3. Project Management] Jacksonville Bike Shop is behind on a custom bike and needs to crash 1 day of time from the 6-step project. Given the project table below answer the following questions. Suppose this shop calls the customer and asks for a project extension, reducing the amount of time she/he nceds to crash. [Note: The project can be speeded up (or "crashed") by spending For example, activity A currently takes 10...
4. Given the data and information that follow, compute the total direct cost for each project duration. If the indirect costs for each project duration are $90 (15 time units), $70 (14), $50 (13), $40 (12), and $30 (11), compute the total project cost for each duration. What is the optimum cost-time schedule for the project? What is this cost? Act. Crash Cost (Slope) Maximum Crash Time Normal Time Normal Cost WNUNUNAW OWLOI- 100 60 200 200 $730 Initial project...
2. A student has developed a project and is interested in accelerating the schedule. Below network diagram (Activity on Arrow) and table show all information needed. Partial crashing is available. Show your work for crashing. Accelerated Duration Cost Present Duration Cost $100 4 $50 5 $250 2 $200 3 a h 3 $100 $350 C d 3 $100 cannot accelerate 6 $100 $150 e f 7 $300 5 $600 a) Without any crashing (acceleration), how long is the project expected...
Q.3. Assume the network and data that follow. Compute the total direct cost for each project duration. If the indirect costs for each project duration are S410 (19 time units), S360 (18), S310 (17), and $260 (16), compute the total project cost for each duration. What is the optimum cost-time schedule for the project? What is this cost? Activity Crash Cost (Slope) Maximum Crash Time Normal Time Normal Cost 20 60 50 60 70 50 100 90 50 S470 10...
15. Given the following project (all times are in days): Pre- Normal Normal Crash Crash Activity decessor Time Cost Time Cost $50 200 160 a, c a, c 290 100 180 (a) Draw the network and find the critical path, time, and (b) Calculate the crash cost-per-day (all activities may be (c) Find the optimal way of getting an 18-day delivery (d) Find the optimal way of getting a 16-day delivery (e) Calculate the shortest delivery time for the project....