Angle of force F with horizontal,
= 90 - 60 = 30 deg
Moment of F about point A,
M1 = -125 cos 30 * 3
M1 = 324.75 lb.in
Moment of P about point A,
M2 = [P cos (90 - 20) * 1.5] + [P sin (90 - 20) * 14]
M2 = 13.668 P
Net moment about A = 0
so, M1 - M2 = 0
324.75 - 13.668 P = 0
P = 324.75 / 13.668
P = 23.76 Ib
Practice Ch1-10 ) 207 il takes a force of F 125lb to pull the nail out...
The crowbar is subjected to a vertical force of P-26 lb at it takes a force of F 17o lb at the ca to puil the nail out. The crowbar contacts the board at point A. (Figure 1) and negative value if the Express your answer using three significant figures. Enter positive value if the moment is moment is clockwise. Mp Ib-in Part B Find the moment of the force F about point A Express your ans er using three...
In order to pull out the nail at B, the force F exerted on the handle of the hammer must produce a clockwise moment of 410 lb- in about point A (Figure 1) Part A Determine the required magnitude of force F Express your answer with the appropriate units. Figure 1 of 1 > P 10.52 lb 30° Smit Previous Answers Request Answer Incorrect; Try Again; 3 attempts remaining 18 in. Provide Feedback
In order to pull out the nail at B, the force F exerted on the handle of the hammer must produce a clockwise moment of 500 lb*in. about point A. Determine the required magnitude of force F. 30° 5 in. 18 in.
Learning Goal: To determine the maximum shear force that can be applied to two shafts of varying cross sections: a solid square shaft and a hollow square shaft. The two square cross sections shown below (Figure 1) are each subjected to a vertical shear force, V. The side length of each cross section is s = 6.00 in and the side length of the hollowed- out portion of the second cross section is r = 2.25 in. The maximum allowable...
Learning Goal: To calculate torsional deformation and shear stress due to an applied force in a door handle design. A locked door handle is composed of a solid circular shaft AB with a diameter fb = 105 mm and a flat plate BC with a force P = 76 N applied at point C as shown. Let c = 543 mm, d = 125 mm, and e = 145 mm. (Treat the handle as if it were a cantilever beam.)...
Learning Goal: To calculate torsional deformation and shear stress due to an applied force in a door handle design. A locked door handle is composed of a solid circular shaft AB with a diameter of b = 101 mm and a flat plate BC with a force P = 77 N applied at point C as shown. Let c = 473 mm, d = 126 mm, and e = 148 mm (Treat the handle as if it were a cantilever...
To calculate the resultant couple and force at a point for a given force and couple system. Two forces F1F1F1 = 75 NN and F2F2F2 = 255 NN and two moments M1M1M1 = 100 N⋅mN⋅m and M2M2M2 = 50 N⋅mN⋅m act on the beam as shown in (Figure 1). DO NOT ATTEMPT TO ANSWER IF YOU ARE NOT AN EXPERT, AVOID BEING REPORTED, ONLY ANSWER IF YOU TRULY KNOW WHAT YOU ARE DOING AND ARE AN EXPERT IN THE SUBJECT!...
Learning Goal: To calculate torsional deformation and shear stress due to an applied force in a door handle design. A locked door handle is composed of a solid circular shaft AB with a diameter fb = 105 mm and a flat plate BC with a force P = 76 N applied at point C as shown. Let c = 543 mm, d = 125 mm, and e = 145 mm. (Treat the handle as if it were a cantilever beam.)...
Solve for E please Review (MR).= -2.88 kN-m Submit Previous Answers Learning Goal: To determine the location and direction of a single equivalent force for a coplanar force system. The frame shown in (Figure 1) has dimensions H = 3.1 m and L = 0.9 m and is subjected to the forces P1 = 4.5 kN, P2 = 8.5 kN, and P3 = 11.5 KN. Force P3 is applied Ay = 0.4 m down from the top. ✓ Correct Part...
We were unable to transcribe this image10 of 10 > PartD A force is applied to a block sliding along a surface (Figure 2). The magnitude of the force is 15 N, and the horizontal component of the force is 4.5 N. At what angle (in degrees) above the horizontal is the force directed? Express your answer to two significant figures View Available Hint(s) ㆁ图 Submit 809 PM 1/27/2019