Question

A wild-type male mates with a hermaphrodite that is both unusually long (lon) and has uncoordinated (unc) movement. All of the F, male offspring are long but with normal movement, while all of the F, hermaphrodite offspring are normal in both body length and movement. a. What can you determine about the linkage or chromosomal locations of the lon and the unc genes? among the cross-progeny in the F, generation, and in what proportions? expected in the F, generation, and in what proportions? b. If the lon F, males are mated to the F, hermaphrodites, what phenotypes are expected c. If the F, hermaphrodites are instead allowed to self-fertilize, what phenotypes are
0 0
Add a comment Improve this question Transcribed image text
Know the answer?
Add Answer to:
A wild-type male mates with a hermaphrodite that is both unusually long (lon) and has uncoordinated...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • In C. elegans, lon-2 and unc-2 are recessive mutations that are 8 map units apart on...

    In C. elegans, lon-2 and unc-2 are recessive mutations that are 8 map units apart on the X chromosome. A hermaphrodite who is Lon and Unc is mated to a wild-type male. An F1 hermaphrodite is mated to a wild-type male. What are the expected percentages of the different phenotypes among the male progeny?

  • A male with the genotype Dd uu is mated to a hermaphrodite of genotype dd Uu.  What...

    A male with the genotype Dd uu is mated to a hermaphrodite of genotype dd Uu.  What is the probability that any one of their progeny will have normal phenotypes for both traits? *Note: the normal phenotype is recessive for dd and the normal phenotype is dominant for Uu.

  • The following pertains to questions 1-2. Let's say you EMS treat C. elegans, scan for interesting phenotypes, and pick an adult hermaphrodite with an unusually long body. The long body pheno...

    The following pertains to questions 1-2. Let's say you EMS treat C. elegans, scan for interesting phenotypes, and pick an adult hermaphrodite with an unusually long body. The long body phenotype is referred to as Lon. You establish a homozygous true breeding Lon mutant strain and name it lon-9. Through crosses you discover that the lon-9 mutant allele is recessive. Let's say you work out that the lon-9 gene is X-linked. Ion-2 is an X-linked gene and the Ion-2(e432) allele...

  • The Gumienny lab is trying to clone a gene that affects body size in the roundworm...

    The Gumienny lab is trying to clone a gene that affects body size in the roundworm C. elegans. A mutation in this gene, called sma-12, makes small animals when homozygous. It was isolated in a screen that used the chemical mutagen ENU. sma-12 was mapped to Chromosome V (5). To more finely map the location to identify the causative mutation, they perform a two-factor mapping experiment with another Chromosome V-linked gene, unc-23, which has a known position on Chromosome V....

  • Short Answer 28. Given the following information: Tall (T) is dominant over short (t), brown hair...

    Short Answer 28. Given the following information: Tall (T) is dominant over short (t), brown hair (B) is dominant over red hair (b), and a great sense of humor (H) is incompletely dominant over a being not funny (h). (Note: the inheritance patterns described are not factual!). The following cross is performed: Dr. Peter Linder (TtBbHH) x Dr. Carol Linder (TTbbHh) a. What is the probability that at least one of their children will be of tall, red- haired and...

  • 7.) Haemophilia is an X-linked recessive disorder. If a male haemophiliac mates with a normal (non-haemophiliac)...

    7.) Haemophilia is an X-linked recessive disorder. If a male haemophiliac mates with a normal (non-haemophiliac) homozygous woman, would the progeny be affected? a. All males would be carriers. All females would be normal. b. All males would be normal. Half of the females would be carriers and half of the females would have haemophilia. c. All males would be normal. All females would be carriers. d. Half of each sex would be normal and half of each sex would...

  • On the island of Notion, in the Factotum Archipelago, there lives a population of pencil bears....

    On the island of Notion, in the Factotum Archipelago, there lives a population of pencil bears. A portion of these bears have silky fur, and as a result, are much better surfers. The texture of the fur is determined by a single autosomal locus with two alleles: S (trait allele) and s (wild type allele). In a recent study, researched collected the values in the following table: Table 1. Counts of Pencil Bear fur style by genotype Phenotype Genotype Silky...

  • Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in...

    Bio215 Problem Questions Hassanaton MULTIPLE CHOICE 1) Pea plants were particularly well suited for use in Mendel's breeding experiments for all of the following reasons exep that ) peas show easily observed variations in a number of characters, such as pea shape and flower color. B) it is possible to completely control matings between different per plants. C) it is possible to obtain large numbers of progeny from any given cross. D) peas have an unusually long generation time. E)...

  • Fun-filled Genetics activity Set Psa plants were particularly well suited for use in Mendel's breeding experiments...

    Fun-filled Genetics activity Set Psa plants were particularly well suited for use in Mendel's breeding experiments for all of the following m e thal Al was show easily terved various in a number of characters, such as a shape and flower color, it is powible to completely control tingshotween different pe plants, it is possible to a large numbers of progeny from any given cross. Dipeas have unusually long generation time, many of the observable characters that vary in pea...

  • #1. In peas, flower location and plant height are controlled by genes that follow Mendel’a law....

    #1. In peas, flower location and plant height are controlled by genes that follow Mendel’a law. One allele at each locus is donminat to the other at that locus: (i) AXIAL FLOWERS (A), terminal flowers (a), and (ii) TALL PLANT (T), short plant (t). A pure breeding plant for the dominant traits is mated with pure breeding plant for the recessive traits. What possible gametes can F1 individuals that interbreed make? HWS, Check canvas for due date 20 pts NAME...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT