If you add AgCl to a 0.10 M solution of NaCl(aq), will the solubility of AgCl...

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Answer 1

Answer #1

Ksp of AgCl = 1.77×10^–10

AgCl ---------------> Ag+ + Cl-

Ksp = [Ag+][Cl-]

1.77×10^–10 = S^2

S = 1.33 x 10^-5 M

solubility in water = 1.33 x 10^-5 M

when NaCl added :

AgCl ---------------> Ag+ + Cl-

S 0.1

Ksp = [Ag+][Cl-]

1.77×10^–10 = S x 0.1

S = 1.77 x 10^-9 M

solubility when NaCl added = 1.77 x 10^-9 M

so the solubility of AgCl less than that of water

Answer 2

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