Solution :
Given that ,
mean = = 63.6
standard deviation = = 2.5
a) n = 200
P( 58 < x < 80 ) = P[(58 - 63.6 )/ 2.5 ) < (x - ) / < ( 80 - 63.6 ) / 2.5 ) ]
= P( -2.24 < z < 6.56 )
= P(z < 6.56) - P(z < -2.24 )
Using z table,
= 1 - 0.0125
= 0.9875
= 0.9875 * 200 = 197.5
= 197 women
Assume that the heights of women are normally distributed with a mean of 63.6 inches and...
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