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The beam is subject to the two shear forces V1 = 6 kip and V2 3 kip. A 6 in. B 1 ft 1 ft 3 in. Part A Determine the absolute

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FBD of the beam V, = 6 kip Yox 1223 kép > A Ibin RAX B kt 3in PAY ABY lft ift kift Area of cross section (A) = 6*3 in ² =18 iFBDC Sheare force) OS X 1 q vcx) Ray N(X) today 20 7 v(x) = -115 kip ISKS2; du qv(x) Bay X V(x) + Ray = 4 or V(X) = 6-115 punShear free diagram Y A 4.5 x -pa5 - 3 Max Sheare free on the beam Iman =4.5 kep Max shear stress in the beam てmam Vmax 4.5 18

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