Question

4 The beam in the figure below is in equilibrium and loaded as shown.c calculations HOW is in equilibrium and loaded as shown Calculate the magnitude of FA and FD. Show all 15 ft 10 ft 10 ft Fe=50,000 lbs Fo=20,000 lbs w=4,000 lbs/ft B 30°

Answer 1

solution is attached in the image posted below.

hope it helps.

Sroto 20,000 lbs 4000 Ibls IFL 18 10 10 The load of soooo is inclined resolving it into two direction then feefy fe to fy-f sine = f sin 30 30% fy > 50,000 sin30 -> SOUo los fo= fcose -> Socco cos30 => 4330127 lbs 25CCO 20.000 eurvolle iht that the to AT & 12801.25 5 10 10 Now using equilibrium equation - – C4 0 RA Ror urco x 35 + 206+25000 - 185000 lbs

Taking moment about A:- {ma=o Ucoox 35? *25000X15 + 20000 x25 2 -Rox 35=0 Roz asocolo RA= 185cco - asoro => qocco Lb Hence Reaction at A&o RA: 90,000 lb T Ro= asooo 1o T There will also be a horizontal force fx= 433021.2715 so as there are is no information of supports hence it can be kept as such.