Question

Part A and B please...

Problem 10.99 ③ 13 ore The radius of the rol of paper shown in the figure (Figure 1) is 7.7 cm and its moment of inertia is I -3.3x10-kg.m". A force of 24 Nis exerted on the end of the roll for 1.38, but the paper does not tear so it begins to unroll. A constant friction forgue of 0.13 m. N is exerted on the roll which gradually brings it to a stop, Constants Periodic Table Assuming that the paper's thickness is negligible, calculate the length of paper that unrols during the time that the force is applied (1.35). Express your answer using two significant figures. 30 AED RO? Figure < 1 of 1 > Submit Previous Awes Best An X Incorrect; Try Again; 2 attempts remaining Part B Assuming that the paper's thickness is negligible, calculate the length of paper that unrolls from that the need in the time when the will hanned m inn Pearson

Answer 1

Tosque due to applied force 7. = Ky F = 0.077% 2-4 = 0.1848 N-24 = 16.606hadden Het forque = Za - Tyriction Zout = 0.1848– 0.13 = 0.0548 Nowy hence angules aceleration will be That IK azer 0548 3.3x10-3 haspte Now apply kinematic eph D = Wo + ļ < t = 0 + 1x 16.6068132 8 = 14.03 vad. these fare dength = 10 = 0.077x14:03 = 1.084 km B.) angulas relocity at end of force affled W = Wotat => w=0+ 16-606813 -) w = 21:58 hadde angular acceleration due to frictional fosque I 4 = Zbruction => y = 0.13 3.3x10-3 .. Now affly kinematica agh nya y = 39-39 vedfyn :00 = wž 24% => [= (21958) = 5.91 Mad these fare length = rog = 0.07745.91 = [0.455m 7 Am