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11.2 kV 11.2 kV Şoor Bus-1A 230 kV Bus-1B 230 kV CB св. Fig. 1 Fig. 1 shows a part of a power system having four synchronous

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see part (a) taking Base MUA = 50MUA = Se 11-2 KV (1) for generator 9 1 8 G2 Xpu = Xpu (new) Old) Xpu = 0.15 Old) UB (new) XpPer unit dig. (without XR) jo.0375 10.0375 selor jo.125 as fault occur at location 1 We have to calculate XTH at point ② XTHXTH = X211 X2 = 0.2 ||0:1375 XTH = (0.1). (0-1375) 0.1 +0.1375 XTH = 0.0579 pu Fault current If - VTH UTH=1 pe (PU) XTH X TH=XR = ? to limit fault level = 800 MUA XR jo.0375 jXTI jo.0375 jXT2 jxg, jo.125 jo.125 T6XE jXg3 jo.2 jo.2 hox! as fault locatIf = VTH XTH VTH=1pu, If = 16 pe XTH = 10.1XR+ 0.0130 10.2375+XR 16 = 0.1XR+ 0.0138 10.2375+XR. 16 (0:1 XR +0.0130) = 0.2375+

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