Question

The actual concentration was found to be 0.002364 M.

4. Knowing that 1 mole of dissolved oxygen ends up reacting with 4 moles of the titrant S2032, how do you calculate the amount of dissolved oxygen (in units of mg/L) from the volume of titrant added? Show your work. (2.5 pts) • Use X (mL) as your total volume of titrant added. • Use the actual concentration of the -0.0025 M NazS2O3 solution used during the titration (calculated in question #3). Given that the MnO(OH)2 (s) precipitate forms when the water sample (5 mL) MnSO, solution (1 ml), and alkaline azide solution (1 mL) are added together. assume a total sample volume of 7 mL that is titrated with -0.0025 M NaSO. Calculate what you need to multiply by X (mL) to get the dissolved oxygen concentration in units of mg/L.

Answer 1

The concentration of dissolved oxygen is calculated:

[O2] = 0.002364 mol S2O3-2 / L * (1 mol O2 / 4 mol S2O3-2) * (32000 mg O2 / 1 mol O2) = 18.91 mg / L

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