An object is placed 40 cm to the left of a convex lens that has a focal length f = +10 cm. a) Draw the ray diagram (3 rays) and find the image. b) What is the distance the image is from the lens? c) Is the image real or virtual? d) What is the magnification?
An object is placed 40 cm to the left of a convex lens that has a focal length f= +10 cm. a) Draw the ray diagram (3 rays) and find the image. b) What is the distance the image is from the lens? c) Is the image real or virtual? d) What is the magnification?
Problem 5) a) An object is 80 cm to the left of a lens of focal length +40 cm. Where is the image? Is it real or virtual? Is it erect or inverted? What is its magnification? Draw the ray diagram. (2pt.) b) A second lens, of focal length +50 cm, is 120 cm to the right of the first lens. What is the distance between the final image and the first lens? Draw the ray diagram. (2pt.) 1
7. An object is placed at a distance of 80 cm left of a converging lens with a focal length of 30 cm. . Calculate the image distance. Is the image virtual or real? If the object is 8 cm tall, what is the size of the image? A diverging lens with the same focal length is placed 10 cm right of the first lens. Determine final image position and magnification. 8. A light ray strikes a flat piece of...
Two converging lenses are placed 20 cm apart. An object is placed on the left of the first lens, at a distance of 30 cm. The first lens has a focal point of 10 cm and the second lens has a focal length of 20 cm. a) Using a ray diagram determine the type of image formed by the first lens. b) Calculate the position of the image formed by the first lens. c) Find the magnification of the image...
An upright object 1.75 cm tall is placed 38.0 cm to the left of a converging lens having a focal length f1 = 28.0 cm. A converging lens of focal length f2 = 18.0 cm is placed 108 cm to the right of the first lens. (4points) Determine the final position of the final image. (4 points) Determine the total magnification of the final image. (3 points) Is the final image upright or inverted? Please show all step when solving...
6. An object is placed at a distance of 60 cm left of a converging lens with a focal length of 20 cm. Calculate the image distance. Is the image virtual or real? . If the object is 10 cm tall, what is the size of the image? Now another lens of focal length 16 is placed 12 cm right of the first lens. Determine the image position and magnification
11.87 A 1.00-cm-high object is placed 4.85 cm to the left of a converging lens of focal length 8.20 cm. A diverging lens of focal length - 16.00 cm is 6.00 cm to the right of the converging lens. Find the position and height of the final image. position Take the image formed by the first lens to be the object for the second lens and apply the lens equation to each lens to locate the final image. cm 8.442...
(4) When an object is placed at a distance of 8 cm from a lens, the magnification is -5. (a) What is the focal length of the lens? (b) If the object is placed at 10 cm from the same lens, what is the magnification of the image? <Real Virtual> (c) Characterize the image formed in (b) by I <no image forms> <Upright:Inverted> <Enlarged: Unmagnified:Reduced> 1 and tell why
A 4.0 cm tall object is placed 12.0 cm in front of a diverging lens. When the image of the object is measured it is found to measure 1.3 cm in height. What is the focal length of the lens? Draw a ray diagram with the object, image and focal points labeled.