Question

Consider an imaginary bacterial cell that contains equal concentrations of 1000 different enzymes in solution in the cytosol. Each protein has a molecular weight of 80000. The cytosol has a specific gravity of 1.17 and contains 18.1% soluble protein by weight (the protein fraction consists entirely of enzymes). Calculate the molar concentration of each enzyme in this cell. molar concentration of each enzyme: Assume that the bacterial cell is a cylinder (diameter 1.00 um, height 2.00 pm). Calculate the number of molecules of a single enzyme in the cell. number of molecules per enzyme: molecules/cell

Answer 1

1000 different enzymes in solution in the cytosol. Each protein has a molecular weight of 80000. The lytosol has a specific gravity of 1017 and contains 18.2% soluble profein by weight : Specific Gravity = - Density of Ce fosil Density of water at 4°C Density of lyfosol = 1.17 x 1000 kg/m3 = 1170 kg Density of Cytosol = 1170 kg = 10170 kq 1000 → Il solution of lytosol contain 1.170 kg. Mass of soluble Profein = 18.1 x 170 = 0.211 77 kg Moles of Profein Enzyme = 0.2 1177*1500 g = 2.6471258153 mole. 80000 g/mol Concentration of Profein (enzyme = moles of Profein Volume of solution Concentration of protein / enzyme = 2.647125 x 10-3 mole 1 L I concentration of profünf enzyme = 2.6478 10-3 M ] Concentration of each enzynne = 2.647X10-3 m love cock, Чт 2 мм = 2-642 х 10- 6м | Conceмat on ч

→ Cylinder :- Radius = 0.5um diameter 1 um height = 2um. - Volume of Cylinder = Volume of Cylinder 182h Mx (0.5x10-6) 2 (2x10-6) m3 Volume of Cylinder- 1.571810-18 m3 y volume of Culinder = 10571x18-15 L Concentration of each Enzyme = 2.647x10-6 M Volume of cylinder = 1.571x10-15 L Mole of each enzyme = 2.647810-6 mos x 1.571810-15 L mole of each enzyme = 4.15579 x 10-21 mole Number of molecules of enzyme = 4.15579818-21 x 6.022 x 1023 Number of Molecules of enzyme = 25.0262 4102 Number of molecules of enzyme = 2,502.6 Z 2,503 Number of molecules per enzyme :- 2,503 moleules / cello