The oxidation of 25 mL of a solution containing Fe2+ requires 29 mL of 0.0230 M K2Cr2O7 in acidic solution. Balance the following equation. Do NOT include the states of each species. Cr2O72− + Fe2+ + H+ → Cr3+ + Fe3+ → Calculate the molar concentration of Fe2+: M
Answer
0.1601M
Explanation
The balanced chemical equation is
Cr2O72- + 6Fe2+ + 14H+ --------> 2Cr3+ + 6Fe3+ + 7H2O
Stoichiometrically , 1mole of Cr2O72- react with 6moles of Fe2+
Moles of Cr2O72- consumed = (0.0230mol/1000ml) × 29.0ml = 0.000667mol
moles of Fe2+ present in the solution = 6 × 0.000667mol =0.004002mol
Molar concentration of Fe2+ = ( 0.004002mol/25ml ) ×1000ml = 0.1601M
The oxidation of 25 mL of a solution containing Fe2+ requires 29 mL of 0.0230 M...
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The concentration of a Fe2+ solution
is determined by titrating it with a 0.1462 M
solution of Ce4+. The balanced net
ionic equation for the reaction is shown below.
Ce4+(aq)
+ Fe2+(aq)
Ce3+(aq)
+ Fe3+(aq)
In one experiment, 16.48 mL of the
0.1462 M Ce4+ solution
is required to react completely with 25.00 mL of
the Fe2+ solution. Calculate the
concentration of the Fe2+ solution.
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