1)
Given:
k = 0.398 M/min
use relation between rate constant and half life of 0 order
reaction
t1/2 = [A]o/(2*k)
= 6.2/(2*0.398)
= 7.789 min
Answer: 7.79 min
2)
Keq << 1
So, there will be more reactant than products at equilibrium
Answer: option 5
1) 2) Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of...
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