Question

1)

Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of 0.398 M/min. The re

2)

The equilibrium constant for the gas phase reaction 2503 (g) = 2502 (g) + O2 (g) is Keq = 2.2 x 10-9 at 999 K. At equilibrium

0 0
Add a comment Improve this question Transcribed image text
Answer #1

1)
Given:
k = 0.398 M/min
use relation between rate constant and half life of 0 order reaction

t1/2 = [A]o/(2*k)
= 6.2/(2*0.398)
= 7.789 min
Answer: 7.79 min

2)
Keq << 1
So, there will be more reactant than products at equilibrium
Answer: option 5

Add a comment
Know the answer?
Add Answer to:
1) 2) Suppose the surface-catalyzed hydrogenation reaction of an unsaturated hydrocarbon has a rate constant of...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT